---
title: "Reading Kinship: Phylogenetic Trees"
book: "High School Biology"
subject: biology
language: en
chapter: 26
exercises: 15
source: https://one-course.com/books/biology/2/en/chapter/26-reading-kinship-phylogenetic-trees
---

# Chapter 26 — Reading Kinship: Phylogenetic Trees

In 1837, on a page of a private notebook, Darwin sketched a branching line with a few twigs and wrote above it two words: "I think". The sketch proposed that [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) are related as the twigs of a tree are — by descent from common branches — and that their kinship could be reconstructed. Today the sketch is a standard tool: a [phylogenetic tree](#def-g12-phylogenetic-trees-tree), built from shared characters and from [DNA](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-information), read according to rules. This chapter teaches those rules: how to build a tree from a table of characters, how to read one without misreading it, and how molecules turn it into a clock.

## 26.1 What a tree says

**Definition 26.1 (Phylogenetic tree).**

A *phylogenetic tree* is a diagram of the kinship of a set of [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) (or other groups). Its tips are the [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) compared; each *node* where two branches meet represents their most recent common ancestor — a hypothetical [population](https://one-course.com/books/biology/2/en/chapter/25-selection-drift-and-speciation#def-g12-selection-drift-speciation-population), not a known fossil; the *root* is the common ancestor of all. Two [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) are closer kin than a third when their common ancestor (their node) is more recent than the node they share with the third. Kinship is read from the nodes, never from the left-to-right position of the tips.

**Proposition 26.2 (Rules of reading).**

- A tree can be rotated at any node without changing its meaning: the order of the tips is arbitrary.
- A node has no name and is not one of the tips: a [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) is never the ancestor of another [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) on the tree; two tips are *sister groups* , descended from a shared ancestor.
- A group made of an ancestor and *all* its descendants — everything beyond one node — is a *clade* , the only kind of group a phylogenetic classification names.
- Branch lengths carry information only if the tree says so (time, or number of changes); otherwise only the branching order counts.

**Proof.** *Admitted at this level.* ∎

![Two drawings of one tree. Rotating the branches at each node changes the order of the tips but not a single kinship: in both, mouse and human are sisters, the lizard is their closest relative, and the frog is the most distant. Reading "the lizard is between the frog and the mouse" from tree A would be a mistake.](https://one-course.com/images/onecourse/chapters/biology-2/g12-phylogenetic-trees/fig-0dcd3463ad2a.svg)

*Two drawings of one tree. Rotating the branches at each node changes the order of the tips but not a single kinship: in both, mouse and human are sisters, the lizard is their closest relative, and the frog is the most distant. Reading "the lizard is between the frog and the mouse" from tree A would be a mistake.*

**Example 26.3 (Misreadings to avoid).**

"Humans descend from chimpanzees": no — on the tree, humans and chimpanzees are sister tips, descended from a common ancestor that was neither. "The frog is more primitive": no — every tip is a present [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) with the same length of history since the root; the frog lineage has evolved for as long as ours. "The lizard is closer to the frog than to the mouse" (from tree A): no — lizard and mouse share a more recent node.

## 26.2 Building a tree from characters

**Definition 26.4 (Ancestral and derived states).**

A *character* is a feature that varies among the [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) compared (the presence of a vertebral column, of four limbs, of an amniotic egg, of hair). Each character has an *ancestral* state — the one the common ancestor of the group had — and one or more *derived* states that appeared later in some lineage. Only *shared derived states* indicate kinship: two [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) sharing a derived state inherited it from the ancestor in which it arose. A shared ancestral state says nothing, since everyone’s ancestor had it.

**Method 26.5 (From a character matrix to a tree).**

1. Make a table: [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) in rows, characters in columns, 1 for the derived state and 0 for the ancestral one. Decide which state is ancestral by comparing with an *outgroup* , a [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) known to be outside the group studied.
2. Find the derived state shared by the most [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) : it defines the first, largest [clade](#prop-g12-phylogenetic-trees-rules) . Within it, find the next most widely shared derived state, and so on.
3. Draw the nested [clades](#prop-g12-phylogenetic-trees-rules) as a tree: each shared derived state marks one node, and the character is written on the branch where it appeared.
4. Check for conflicts: a character shared by [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) that other characters place apart either arose twice (convergence) or was lost once. Choose the tree that requires the fewest changes in all — the most *parsimonious* tree.

![From matrix to tree. Each derived state (1) shared by a set of species marks the node of their common ancestor; the red bars show where each character appeared. The lamprey, lacking every derived state, is the outgroup that fixes the ancestral states.](https://one-course.com/images/onecourse/chapters/biology-2/g12-phylogenetic-trees/fig-2e95b0985438.svg)

*From matrix to tree. Each derived state (1) shared by a set of [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) marks the node of their common ancestor; the red bars show where each character appeared. The lamprey, lacking every derived state, is the outgroup that fixes the ancestral states.*

**Example 26.6 (A conflict resolved by parsimony).**

Add "wings" to a matrix with bat, pigeon and mouse. Wings would group bat with pigeon; hair and milk group bat with mouse. A tree with bat and mouse together needs wings to have arisen twice (two changes); a tree with bat and pigeon together needs hair, milk, the mammalian jaw and a dozen other characters to have arisen twice each. The first tree is far more parsimonious: wings are a convergence, the mammalian characters a common inheritance. Parsimony does not prove the tree; it chooses the least improbable one.

## 26.3 Trees from molecules

**Proposition 26.7 (Molecular phylogeny).**

A [gene](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-gene) or [protein](https://one-course.com/books/biology/2/en/chapter/14-from-gene-to-protein#def-g11-gene-expression-protein) shared by all the [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) compared is a character matrix in itself: each position of the sequence is a character, and each [nucleotide](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-nucleotide) or [amino acid](https://one-course.com/books/biology/2/en/chapter/1-the-chemical-makeup-of-living-things#def-g10-chemistry-of-life-families) a state. Aligning the sequences and counting the differences between every pair gives a distance matrix, from which a tree is built by joining the closest pairs first. The molecular tree, computed from sequences that owe nothing to anatomy, matches the anatomical tree in the great majority of cases — the strongest test of both.

**Evidence.** [Chapter 6](https://one-course.com/books/biology/2/en/chapter/6-body-plans-and-common-ancestry#ch-g10-common-ancestry) gave the cytochrome c distances of the [vertebrates](https://one-course.com/books/biology/2/en/chapter/6-body-plans-and-common-ancestry#def-g10-common-ancestry-bodyplan), which reproduce the boxes drawn from their skeletons. Among the primates, sequences of dozens of [genes](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-gene) agree: human and chimpanzee differ by about 1.2% of their [DNA](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-information), either from the gorilla by 1.6%, the three from the orangutan by 3%, and the great apes from the macaque by 7%. A tree built from any one of these [genes](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-gene) has the same shape; the few exceptions concern the most recent nodes, where the differences are smallest. ∎

![The tree of five primates from DNA comparison. Human and chimpanzee are sister groups; the gorilla joins them next, then the orangutan, then the macaque. The percentage on each branch is the DNA difference between the species it joins; the dates below come from the molecular clock calibrated by fossils.](https://one-course.com/images/onecourse/chapters/biology-2/g12-phylogenetic-trees/fig-29a05e88bf39.svg)

*The tree of five primates from [DNA](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-information) comparison. Human and chimpanzee are sister groups; the gorilla joins them next, then the orangutan, then the macaque. The percentage on each branch is the [DNA](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-information) difference between the [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) it joins; the dates below come from the molecular clock calibrated by fossils.*

**Proposition 26.8 (The molecular clock).**

For a given [gene](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-gene), differences between two lineages accumulate at a roughly constant rate over long periods, since most substitutions are neutral and fix by drift at the rate at which they arise. The number of differences between two [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) is therefore proportional to the time since their common ancestor. Calibrated on one node dated by fossils, the clock dates the others — with the caution that rates differ between [genes](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-gene) and between lineages, and that the calibration carries its own uncertainty.

**Proof.** *Admitted at this level.* ∎

![The molecular clock among primates: DNA difference against the age of the common ancestor. The points fall close to a straight line of about 0.27% per million years; the line lets a node without fossils be dated from its DNA difference.](https://one-course.com/images/onecourse/chapters/biology-2/g12-phylogenetic-trees/fig-cd055125c9a8.svg)

*The molecular clock among primates: [DNA](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-information) difference against the age of the common ancestor. The points fall close to a straight line of about 0.27% per million years; the line lets a node without fossils be dated from its [DNA](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-information) difference.*

**Example 26.9 (Dating a node).**

Two [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) differ by 4.5% of their [DNA](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-information); at 0.27% per million years, their common ancestor lived some 17 million years ago. The estimate assumes the primate rate applies; for a [gene](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-gene) evolving twice as fast, or in a lineage with shorter generations, the same 4.5% would mean half the time. A clock is only as good as its calibration.

## 26.4 Classification, from trees

**Proposition 26.10 (Classifying by descent).**

A phylogenetic classification names only [clades](#prop-g12-phylogenetic-trees-rules): groups defined by a node and containing all its descendants. Familiar groups that fail this test are not used: "fish" excludes the tetrapods that descend from the same node; "reptiles" excludes the birds that descend from within them; "invertebrates" is everything except a [clade](#prop-g12-phylogenetic-trees-rules). The consequences are worth stating plainly: birds are dinosaurs, the lungfish is closer to us than to the trout, and humans are one branch of the apes, which are one branch of the primates, the mammals, the amniotes, the tetrapods, the [vertebrates](https://one-course.com/books/biology/2/en/chapter/6-body-plans-and-common-ancestry#def-g10-common-ancestry-bodyplan).

**Proof.** *Admitted at this level.* ∎

![Charles Darwin, who first drew the kinship of species as a tree and proposed the mechanism, natural selection, that grows it. Photo Henry Maull and John Fox, c. 1854, public domain.](https://one-course.com/images/onecourse/chapters/biology-2/g12-phylogenetic-trees/img-28a24b6cd2c1.jpg)

*Charles Darwin, who first drew the kinship of [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) as a tree and proposed the mechanism, [natural selection](https://one-course.com/books/biology/2/en/chapter/25-selection-drift-and-speciation#def-g12-selection-drift-speciation-selection), that grows it. Photo Henry Maull and John Fox, c. 1854, public domain.*

**Remark 26.11 (What a tree is not).**

A tree is a hypothesis about history, built from present [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) and tested by every new character and every new sequence; it is redrawn when they disagree, and the redrawing is the work of the field. It has no top and no direction of progress: humans sit at one tip among millions, no higher and no more finished than the lamprey at another. And it has no ancestor at any tip: the ancestors are the nodes, [populations](https://one-course.com/books/biology/2/en/chapter/25-selection-drift-and-speciation#def-g12-selection-drift-speciation-population) gone, whose existence the tree infers and whose fossils, when they are found, sit beside the branches rather than on them.

## 26.5 Exercises

**Exercise 26.1 ★.**

What do the tips, the nodes and the root of a [phylogenetic tree](#def-g12-phylogenetic-trees-tree) represent?

**Solution of Exercise 26.1.**

Tips: the [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) compared. Nodes: their hypothetical most recent common ancestors. Root: the common ancestor of all of them.

**Exercise 26.2 ★.**

In tree A of the first figure, which [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) is the closest relative of the lizard? Of the frog?

**Solution of Exercise 26.2.**

The lizard’s closest relatives are mouse and human together (they share the node just below the lizard’s branch). The frog’s closest relative is the whole group of the other three, equally.

**Exercise 26.3 ★.**

Define a shared derived state and explain why a shared ancestral state does not indicate kinship.

**Solution of Exercise 26.3.**

A state that appeared in an ancestor and was inherited by its descendants; sharing it means sharing that ancestor. The ancestral state was possessed by the ancestor of the whole group, so every [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) could have kept it: sharing it shows nothing about closer kinship.

**Exercise 26.4 ★.**

What is a [clade](#prop-g12-phylogenetic-trees-rules)? Is "birds" a [clade](#prop-g12-phylogenetic-trees-rules)? Is "reptiles" (in the everyday sense)?

**Solution of Exercise 26.4.**

An ancestor and all its descendants. Birds are a [clade](#prop-g12-phylogenetic-trees-rules). "Reptiles" in the everyday sense is not: it leaves out the birds, which descend from within it.

**Exercise 26.5 ★.**

From the primate tree, which is the human’s closest relative, and which node is the oldest?

**Solution of Exercise 26.5.**

The chimpanzee; the oldest node is the one joining the macaque to the apes, 25 million years ago.

**Exercise 26.6 ★★.**

Redraw tree A of the first figure with the human at the top and the frog at the bottom, and check that every kinship is unchanged.

**Solution of Exercise 26.6.**

Rotate at each node: root splits into frog (bottom) and the rest; then lizard, then mouse and human at the top. Mouse and human still share the most recent node, the lizard joins them next, the frog last.

**Exercise 26.7 ★★.**

Add the pigeon (jaws 1, limbs 1, amnion 1, hair 0, feathers 1) to the matrix of the second figure and place it on the tree. What does the character "feathers" add?

**Solution of Exercise 26.7.**

The pigeon has jaws, limbs and amnion: it enters the amniote [clade](#prop-g12-phylogenetic-trees-rules) beside the lizard and the mouse. Feathers, present in one [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species), define no group here; they would define the birds if more birds were added.

**Exercise 26.8 ★★.**

A dolphin has a streamlined body and fins like a shark, and hair, milk and a mammalian jaw. Which tree is most parsimonious, and what are the fins?

**Solution of Exercise 26.8.**

Hair, milk and the jaw place the dolphin among the mammals; putting it with the shark would require all the mammalian characters to have arisen twice. The fins and streamlined body arose separately in the two lineages: a convergence.

**Exercise 26.9 ★★.**

Using the clock figure, date the common ancestor of two [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) whose [DNA](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-information) differs by 2.2%.

**Solution of Exercise 26.9.**

$2.2/0.27 \approx 8$ million years.

**Exercise 26.10 ★★.**

Explain why the sentence "the chimpanzee is our ancestor" misreads the tree, and write the correct sentence.

**Solution of Exercise 26.10.**

Both are present tips; neither descends from the other. Correct: humans and chimpanzees are sister [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species), descended from a common ancestor, now extinct, that lived about six million years ago and was neither a human nor a chimpanzee.

**Exercise 26.11 ★★.**

Why is the lamprey used as the outgroup in the second figure, and what would go wrong if the mouse were used instead?

**Solution of Exercise 26.11.**

The lamprey is known to lie outside the group of jawed [vertebrates](https://one-course.com/books/biology/2/en/chapter/6-body-plans-and-common-ancestry#def-g10-common-ancestry-bodyplan), so its states are ancestral for them. With the mouse as outgroup, hair, amnion, limbs and jaws would all be read as ancestral and their absence as derived: the tree would be built upside down.

**Exercise 26.12 ★★★.**

Two [genes](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-gene) give different trees for three closely related [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) that separated within a million years of each other. Explain how this can happen without either tree being "wrong", using the shuffle of [alleles](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-gene) in the ancestral [population](https://one-course.com/books/biology/2/en/chapter/25-selection-drift-and-speciation#def-g12-selection-drift-speciation-population).

**Solution of Exercise 26.12.**

The ancestral [population](https://one-course.com/books/biology/2/en/chapter/25-selection-drift-and-speciation#def-g12-selection-drift-speciation-population) carried several [alleles](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-gene) of each [gene](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-gene); when it split twice in quick succession, different [alleles](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-gene) were sorted into the three descendants at different [genes](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-gene), so one [gene](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-gene)’s history groups [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) 1 with 2 and another’s groups 2 with 3. Each [gene](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-gene) tree is right for that [gene](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-gene); the [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) tree is the majority verdict of many [genes](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-gene).

**Exercise 26.13 ★★★.**

The molecular clock of a fast-evolving virus runs at 1% per year; that of a mammalian [gene](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-gene) at 0.3% per million years. Explain why the first is used to trace an epidemic and the second to date the origin of the mammals, and why neither can do the other’s job.

**Solution of Exercise 26.13.**

At 1% per year, viral samples taken months apart already differ measurably: the virus tree resolves who infected whom within an epidemic, but over millions of years the sequence would have been overwritten many times. At 0.3% per million years, a mammalian [gene](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-gene) changes too slowly to see anything within an epidemic but keeps a readable record over 200 million years.

**Exercise 26.14 ★★★.**

A fossil bird with teeth and a long bony tail is found in rocks 150 million years old. Explain why it is placed beside a branch of the tree rather than at a node, and what it tells about the node.

**Solution of Exercise 26.14.**

A fossil is a [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) of its own, with its own derived states, not necessarily the ancestral [population](https://one-course.com/books/biology/2/en/chapter/25-selection-drift-and-speciation#def-g12-selection-drift-speciation-population); it sits on a side branch near the node where feathers appeared. It shows that the node — the common ancestor of birds and their nearest reptilian relatives — is at least 150 million years old and that feathers preceded the loss of teeth and tail.

**Exercise 26.15 ★★★.**

"The tree of life has humans at its top." Discuss in a paragraph with the rules of reading, the equal age of the tips, and the number of tips.

**Solution of Exercise 26.15.**

A tree has no top: rotating any node moves humans to the bottom without changing a kinship. Every present tip has evolved for the same time since the root, so none is more advanced. And humans are one tip among millions, on one branch of the apes; the tree’s shape records descent, not rank.

## 26.6 Problem: Six Species and a Clock

**Problem 26.1.**

Weekend problem — a tree built twice, from a character table and from DNA distances, the two compared, and the nodes dated

Six [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species): shark, salmon, salamander, crocodile, pigeon, cat. The outgroup is the lamprey. Character table (1 = derived):

|  | bony skeleton | four limbs | amniotic egg | feathers | hair | skull opening |
| --- | --- | --- | --- | --- | --- | --- |
| shark | 0 | 0 | 0 | 0 | 0 | 0 |
| salmon | 1 | 0 | 0 | 0 | 0 | 0 |
| salamander | 1 | 1 | 0 | 0 | 0 | 0 |
| crocodile | 1 | 1 | 1 | 0 | 0 | 0 |
| pigeon | 1 | 1 | 1 | 1 | 0 | 0 |
| cat | 1 | 1 | 1 | 0 | 1 | 1 |

[DNA](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-information) differences (%) for one [gene](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-gene):

|  | salmon | salamander | crocodile | pigeon | cat |
| --- | --- | --- | --- | --- | --- |
| shark | 30 | 31 | 30 | 31 | 30 |
| salmon |  | 24 | 25 | 25 | 24 |
| salamander |  |  | 19 | 20 | 19 |
| crocodile |  |  |  | 8 | 15 |
| pigeon |  |  |  |  | 15 |

**Part I — From the characters.**

1. Which derived state is shared by the most [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) ? Name the [clade](#prop-g12-phylogenetic-trees-rules) it defines and the [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) left outside. (The last character is the single opening in the side of the skull that mammals have.)
2. Continue with the next most widely shared states and list the nested [clades](#prop-g12-phylogenetic-trees-rules) .
3. Feathers, hair and the skull opening each occur in one [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) . Do they help to build this tree? What would make them useful?
4. Draw the tree, writing each character on the branch where it appeared.
5. Which [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) is the crocodile’s closest relative according to this table? Which pair cannot be resolved by the table alone?

**Part II — From the [DNA](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-information).**

6. Which pair of [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) has the smallest distance? Join them first.
7. Which [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) joins that pair next? Continue until the tree is complete.
8. Compare the [DNA](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-information) tree with the character tree: where do they agree, and what does the [DNA](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-information) settle that the characters could not?
9. The shark’s distances to all others are nearly equal. Explain why, from the shape of the tree.
10. The crocodile–pigeon distance (8) is smaller than the crocodile–cat distance (15). What does this say about the everyday group "reptiles"?

**Part III — The clock.** Fossils date the separation of the salamander lineage from the amniotes at 340 million years.

11. Using the salamander–amniote distances (about 19%), compute the rate of the clock in per cent per million years. (Both lineages have been changing: the distance counts the changes on both branches.)
12. Date the crocodile–pigeon node and the amniote node (crocodile/pigeon versus cat).
13. Date the salmon node and the shark node.
14. Fossils give about 250 million years for the crocodile–bird split and 310 for the amniote split. Compare with your dates and comment on the accuracy of a [single-gene](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-gene) clock.
15. The shark distances (30–31%) hardly exceed the salmon’s (24–25%) although the shark node is much older. Propose an explanation, and say what it implies for dating very old nodes with this [gene](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-gene) .

**Part IV — Reading and naming.**

16. List the [clades](#prop-g12-phylogenetic-trees-rules) of your tree that contain the cat, from the smallest to the largest.
17. Is "fish" (shark and salmon) a [clade](#prop-g12-phylogenetic-trees-rules) ? Is "amniotes"? Justify.
18. A student says the salamander is "an intermediate between fish and reptiles". Correct the statement in the tree’s terms.
19. A fossil with a bony skeleton, four limbs and no amniotic egg, dated 360 million years, is found. Where does it sit relative to the tree, and what does its date confirm?
20. State the result: the tree of the six [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) (as nested parentheses), the one kinship the [DNA](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-information) settled, and the estimated date of the crocodile–pigeon split.

**Solution of Problem 26.1.**

**1.** Bony skeleton (five [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species)): the bony [vertebrates](https://one-course.com/books/biology/2/en/chapter/6-body-plans-and-common-ancestry#def-g10-common-ancestry-bodyplan); the shark is outside.

**2.** Four limbs: tetrapods (salamander, crocodile, pigeon, cat). Amniotic egg: amniotes (crocodile, pigeon, cat). Nested: bony [vertebrates](https://one-course.com/books/biology/2/en/chapter/6-body-plans-and-common-ancestry#def-g10-common-ancestry-bodyplan) $\supset$ tetrapods $\supset$ amniotes.

**3.** No: a state in a single [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) groups nothing. They would be useful with more [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species) sharing them (other birds, other mammals, other reptiles).

**4.** Root: shark versus the rest (bony skeleton); then salmon versus tetrapods (four limbs); then salamander versus amniotes (amniotic egg); among the amniotes, an unresolved three-way split, with feathers on the pigeon’s branch and hair and the skull opening on the cat’s.

**5.** The table places crocodile, pigeon and cat together but cannot order them: the crocodile’s closest relative is undecided.

**6.** Crocodile–pigeon, 8%.

**7.** The cat (15% from each); then the salamander (19–20%); then the salmon (24–25%); then the shark (30–31%).

**8.** They agree on every nesting; the [DNA](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-information) resolves the amniotes: crocodile and pigeon are sisters, the cat joins them next.

**9.** The shark’s lineage separated before all the others diverged from one another; each of them has been apart from the shark for the same time and shows the same distance.

**10.** The crocodile is closer kin to the pigeon than to the cat — and, by the same logic, than to a lizard; "reptiles" without the birds is not a [clade](#prop-g12-phylogenetic-trees-rules).

**11.** 19% over $2 \times 340$ million years of branch: about 0.028% per million years per lineage, i.e. 0.056% per million years of separation.

**12.** Crocodile–pigeon $8/0.056 \approx 140$ million years; amniote node $15/0.056 \approx 270$ million years.

**13.** Salmon $24.5/0.056 \approx 440$; shark $30.5/0.056
\approx 540$ million years.

**14.** Fossils: 250 and 310; the clock gives 140 and 270. The order is right and the older date close, but the crocodile–bird date is far too young: a single [gene](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-gene)’s rate varies between lineages, and one [gene](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-gene) gives a rough clock at best.

**15.** At large distances many positions have changed more than once, so differences no longer add up: the clock saturates. Old nodes are underestimated by this [gene](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-gene); a slower [gene](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-gene), or many [genes](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-gene), are needed.

**16.** (cat, (crocodile, pigeon)) is the smallest [clade](#prop-g12-phylogenetic-trees-rules) containing the cat: the amniotes; then the tetrapods; then the bony [vertebrates](https://one-course.com/books/biology/2/en/chapter/6-body-plans-and-common-ancestry#def-g10-common-ancestry-bodyplan); then all six with the shark.

**17.** "Fish" is not a [clade](#prop-g12-phylogenetic-trees-rules): the node joining shark and salmon is the root, whose descendants include everything. Amniotes is a [clade](#prop-g12-phylogenetic-trees-rules): crocodile, pigeon, cat and their common ancestor.

**18.** The salamander is a present [species](https://one-course.com/books/biology/2/en/chapter/5-biodiversity-at-every-scale#def-g10-biodiversity-scales-species), not an intermediate; it is the sister group of the amniotes, sharing with them the tetrapod ancestor and lacking the amniotic egg that arose later in their line.

**19.** Beside the branch between the tetrapod node and the amniote node: a tetrapod that is not an amniote. Its date confirms that four limbs existed by 360 million years ago and the amniotic egg appeared later.

**20.** (shark, (salmon, (salamander, (cat, (crocodile, pigeon))))); the [DNA](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-information) settled that crocodile and pigeon are sisters; their split dates, by this [gene](https://one-course.com/books/biology/2/en/chapter/3-dna-a-universal-genetic-molecule#def-g10-universal-dna-gene), to about 140 million years (fossils say 250).