Mathematics · Glossary

What is Arrangements, permutations, combinations?

Also known as: permutation

Definition 2.11 University Mathematics — Year 1 · Chapter 2 — Counting

Let EE be a set with E=n\abs{E} = n and let 0kn0 \leq k \leq n.

  • A kk-arrangement of EE is an injective kk-tuple of elements of EE (an ordered selection without repetition);
  • a permutation of EE is a bijection from EE to itself — equivalently, an nn-arrangement;
  • a kk-combination is a subset of EE with kk elements (an unordered selection without repetition). Their number is written (nk)\binom{n}{k}, read “nn choose kk” .

Examples

Example 2.14 (Adding a constraint)

Continuing the round table: among the (n1)!(n-1)! tables of n3n \geq 3 guests, how many seat two given guests AA and BB apart (not adjacent)? Count the complement. Tables where AA and BB sit together: glue them into a single block — n1n - 1 objects around the table, i.e. (n2)!(n-2)! circular arrangements — then order the pair inside its block (22 ways): 2(n2)!2\,(n-2)! adjacent tables. Hence

(n1)!2(n2)!=(n2)!((n1)2)=(n3)(n2)!(n-1)! - 2\,(n-2)! = (n-2)!\,\bigl((n - 1) - 2\bigr) = (n-3)\,(n-2)!

tables keep them apart. Sanity checks: n=3n = 3 gives 00 (around a triangle, everyone touches everyone) and n=4n = 4 gives 22, easily listed by hand. The gluing trick — treat a forced block as one object, then count its internal arrangements — is the standard cure for adjacency constraints, linear or circular.

Example 2.18 (One identity, two proofs)

The specialization a=2a = 2, b=1b = 1 of the binomial theorem reads

k=0n(nk)2k=3n.\sum_{k=0}^{n} \binom nk\,2^k = 3^n .

Here is the same identity with no algebra at all. The right side counts the words of length nn over the alphabet {0,1,2}\{0, 1, 2\} (product rule). Classify each word by the set KK of positions carrying a nonzero letter: choosing KK with K=k\abs K = k costs (nk)\binom nk, then each position of KK independently carries 11 or 22: 2k2^k ways. The sum rule over kk gives the left side. Beyond the pleasure of agreement, the two proofs have different virtues: the algebraic one generalizes to any value of aa, the combinatorial one explains the formula and adapts to constraints (forbid the letter 22 in the last position, say) that no substitution captures. Keeping both techniques active is the practical skill this chapter trains.

Example 2.6 (Finiteness is essential)

On a finite set, Proposition 2.5 is a powerful shortcut: any injective map from EE to itself is automatically a permutation of EE — half of bijectivity comes for free. Both implications collapse on infinite sets: nn+1n \mapsto n + 1 is injective from N\N to N\N but misses 00, and the map NN\N \to \N sending 000 \mapsto 0 and nn1n \mapsto n - 1 for n1n \geq 1 is surjective but not injective. Whenever this proposition is invoked, the finiteness hypothesis is doing real work — a theme that the weekend problem of Chapter 1 explores from the other side, where infinite sets are precisely those admitting such self-maps.

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