Mathematics · Glossary

What is self-adjoint operator?

Definition 15.4 University Mathematics — Year 3 · Chapter 15 — Compact Operators and the Spectral Theorem

TL(H)T \in \mathcal L(H) is self-adjoint if T=TT = T^* (Exercise 13.8), i.e. Tx,y=x,Ty\langle Tx, y\rangle = \langle x, Ty\rangle for all x,yx, y. Then x,TxR\langle x, Tx\rangle \in \R for every xx (equal to its conjugate).

Examples

Example 15.9

On L2([0,1])L^2(\intcc01), let Tf(x)=01min(x,y)f(y) ⁣dyTf(x) = \int_0^1\min(x, y)f(y)\dd y: a Hilbert–Schmidt operator with real symmetric kernel: compact and self-adjoint. Solving Tf=λfTf = \lambda f: the relation (Tf)(x)=0xyf(y) ⁣dy+xx1f(y) ⁣dy\bigl(Tf\bigr)(x) = \int_0^xyf(y)\dd y + x\int_x^1f(y)\dd y shows u=Tfu = Tf satisfies u=fu'' = -f (two differentiations, legitimate for continuous ff, and TfTf is continuous for fL2f \in L^2: dominated convergence), with u(0)=0u(0) = 0 and u(1)=0u'(1) = 0. So eigenfunctions solve λu=u\lambda u'' = -u, u(0)=0u(0) = 0, u(1)=0u'(1) = 0:

un(x)=sin((n+12)πx),λn=1(n+12)2π2(n0),u_n(x) = \sin\Bigl(\bigl(n + \tfrac12\bigr)\pi x\Bigr), \qquad \lambda_n = \frac{1}{\bigl(n + \frac12\bigr)^2\pi^2} \quad (n \geq 0),

and the spectral theorem asserts — with no Fourier theory — that these sines form an orthonormal basis of L2([0,1])L^2(\intcc01) after normalization (the kernel of TT is 00: Tf=0Tf = 0 forces, by the two differentiations, f=0f = 0 a.e.). The weekend problem runs the same circle of ideas for the vibrating string and extracts ζ(2)\zeta(2) from the trace.

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