T∈L(E,F) (E,F Banach) is compact if the image T(B) of the unit ball is relatively compact in F — equivalently, every bounded sequence (xn) has a subsequence with (Txnk) convergent. Finite-rank operators are compact (bounded sets in finite dimension); the identity of an infinite-dimensional space never is (Riesz’s theorem, Year 2).
Examples
Example 15.3
(a) Diagonal operators on ℓ2: T(xn)=(λnxn) is compact iff λn→0 (Exercise 15.2). (b) Kernel operators on C([0,1]): compact by Ascoli (Exercise 7.7). (c) Hilbert–Schmidt operators: for k∈L2([0,1]2),
(Tkf)(x)=∫01k(x,y)f(y)dy
defines a compact operator on L2([0,1]) with ∣∣∣Tk∣∣∣≤∥k∥L2 (Exercise 15.4: truncating the basis expansion of k exhibits Tk as a limit of finite-rank operators).
Example 15.9
On L2([0,1]), let Tf(x)=∫01min(x,y)f(y)dy: a Hilbert–Schmidt operator with real symmetric kernel: compact and self-adjoint. Solving Tf=λf: the relation (Tf)(x)=∫0xyf(y)dy+x∫x1f(y)dy shows u=Tf satisfies u′′=−f (two differentiations, legitimate for continuous f, and Tf is continuous for f∈L2: dominated convergence), with u(0)=0 and u′(1)=0. So eigenfunctions solve λu′′=−u, u(0)=0, u′(1)=0:
un(x)=sin((n+21)πx),λn=(n+21)2π21(n≥0),
and the spectral theorem asserts — with no Fourier theory — that these sines form an orthonormal basis of L2([0,1]) after normalization (the kernel of T is 0: Tf=0 forces, by the two differentiations, f=0 a.e.). The weekend problem runs the same circle of ideas for the vibrating string and extracts ζ(2) from the trace.