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Mathematics · Glossary

What is Convergent sequence?

Also known as: limit of a sequence

Definition 20.10 High School Mathematics · Chapter 20 — Sequences

A sequence (un)(u_n) converges to the real number ℓ\ell if every open interval containing ℓ\ell contains all the terms unu_n from some index on. We then write lim⁡n→+∞un=ℓ\lim\limits_{n\to+\infty} u_n = \ell.

Equivalently: for every ε>0\varepsilon > 0, there exists N∈NN \in \N such that for all n≥Nn \geq N, ∣un−ℓ∣≤ε\abs{u_n - \ell} \leq \varepsilon.

Convergence of u_n = 2 + (-1)n/n to = 2: given > 0, all terms from the index N on lie in the band [ - , + ].
Convergence of un=2+(−1)nnu_n = 2 + \frac{(-1)^n}{n} to ℓ=2\ell = 2: given ε>0\varepsilon > 0, all terms from the index NN on lie in the band [ℓ−ε, ℓ+ε]\intcc{\ell-\varepsilon}{\ell+\varepsilon}.

Examples

Example 20.22

Let u0=2u_0 = 2 and un+1=12(un+2un)u_{n+1} = \frac{1}{2}\left(u_n + \frac{2}{u_n}\right). One checks by induction that un≥2u_n \geq \sqrt{2} for all nn (the inequality 12(x+2/x)≥2\frac{1}{2}(x + 2/x) \geq \sqrt{2} for x>0x>0 is equivalent to (x−2)2≥0(x - \sqrt2)^2 \geq 0), then that (un)(u_n) is decreasing, since

un+1−un=2−un22un≤0.u_{n+1}-u_n=\frac{2-u_n^2}{2u_n}\leq 0 .

Decreasing and bounded below, (un)(u_n) converges to some ℓ≥2\ell \geq \sqrt{2}, which must satisfy ℓ=12(ℓ+2/ℓ)\ell = \frac{1}{2}(\ell + 2/\ell), i.e. ℓ2=2\ell^2 = 2. Hence un→2u_n \to \sqrt{2}. This is Heron’s algorithm, already used by the Babylonians; its convergence is extremely fast (u3u_3 already gives 2\sqrt 2 to eight decimal places).

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