Physics · Glossary

What is Gravitational field strength?

Definition 4.11 High School Physics · Chapter 4 — Universal Gravitation and Weight

The quantity g=GM/R2g = G M / R^2, in newtons per kilogram, is the gravitational field strength at the star’s surface: the star pulls on each kilogram with gg newtons. On Earth, g=9.81N/kgg = 9.81\,\mathrm{N}/\mathrm{kg}.

Surface gravitational field strength on four worlds: the same 1\, kg bag of sugar weighs 1.6\, N on the Moon and 25\, N on Jupiter.
Surface gravitational field strength on four worlds: the same 1kg1\,\mathrm{kg} bag of sugar weighs 1.6N1.6\,\mathrm{N} on the Moon and 25N25\,\mathrm{N} on Jupiter.
“Down” is a local notion: at every point of the globe the weight vector points toward the center O. Two antipodean walkers both stand upright — feet toward each other.
“Down” is a local notion: at every point of the globe the weight vector points toward the center OO. Two antipodean walkers both stand upright — feet toward each other.

Examples

Example 4.12 (Computing gg)

For the Earth (M=5.97×1024kgM = 5.97 \times 10^{24}\,\mathrm{kg}, R=6.37×106mR = 6.37 \times 10^{6}\,\mathrm{m}):

g=6.67×1011×5.97×1024(6.37×106)2=3.98×10144.06×10139.81N/kg.g = \frac{6.67 \times 10^{-11} \times 5.97 \times 10^{24}}{(6.37 \times 10^{6})^2} = \frac{3.98 \times 10^{14}}{4.06 \times 10^{13}} \approx 9.81\,\mathrm{N}/\mathrm{kg}.

For the Moon (M=7.35×1022kgM = 7.35 \times 10^{22}\,\mathrm{kg}, R=1.74×106mR = 1.74 \times 10^{6}\,\mathrm{m}) the same computation gives gMoon1.62N/kgg_{\text{Moon}} \approx 1.62\,\mathrm{N}/\mathrm{kg} — six times less: the Moon is far lighter, and being smaller does not make up for it. For Mars, gMars3.73N/kgg_{\text{Mars}} \approx 3.73\,\mathrm{N}/\mathrm{kg}.

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