全部书籍

专业

应用 关于 Coach 登录 开始阅读

书籍暂未推出简体中文版——当前显示英文版。

Physics · 术语表

什么是 Signal; sinusoidal signal?

Definition 5.1 University Physics — Year 1 · 第 5 章 — Signal Propagation: Travelling and Standing Waves

A signal is a physical quantity that varies in time and carries information: the acoustic overpressure at a microphone, the voltage at an antenna, the transverse displacement of a point of a string. The sinusoidal signal

s(t)=Acos⁡(ωt+φ)s(t) = A\cos(\omega t + \varphi)

has amplitude A>0A > 0, angular frequency ω\omega (rad/s\mathrm{rad}/\mathrm{s}), frequency f=ω/2πf = \omega/2\pi, period T=1/fT = 1/f and initial phase φ\varphi; ωt+φ\omega t + \varphi is its phase at time tt.

示例

Example 5.14 (Two loudspeakers)

Two speakers 2.0 m2.0\,\mathrm{m} apart play the same 850 Hz850\,\mathrm{Hz} tone in phase (λ=0.40 m\lambda = 0.40\,\mathrm{m}). On the perpendicular bisector δ=0\delta = 0: loud everywhere. Along the segment joining them, δ\delta changes by 2λ2\lambda per wavelength of displacement, so quiet spots (δ=±λ/2,±3λ/2,…\delta = \pm\lambda/2, \pm 3\lambda/2, \dots) sit every λ/2=20 cm\lambda/2 = 20\,\mathrm{cm} — a standing wave, the subject of the next section. Move one speaker’s wire so it plays in opposite phase, and loud and quiet exchange places.

Example 5.15 (Young’s holes)

Two pinholes S1S_1, S2S_2 a distance aa apart, lit by one monochromatic source (so that they emit in phase), send light to a screen at distance D≫aD \gg a. At a point of the screen at height xx from the axis, the path difference is

δ=S2M−S1M≈a xD\delta = S_2M - S_1M \approx \frac{a\,x}{D}

(for x≪Dx \ll D: S1,2M=D2+(x∓a/2)2≈D+(x∓a/2)2/2DS_{1,2}M = \sqrt{D^2 + (x \mp a/2)^2} \approx D + (x \mp a/2)^2/2D, and subtract). Bright fringes at x=nλD/ax = n\lambda D/a: the fringe spacing is

i=λDa.i = \frac{\lambda D}{a} .

With a=0.50 mma = 0.50\,\mathrm{mm}, D=2.0 mD = 2.0\,\mathrm{m}, λ=633 nm\lambda = 633\,\mathrm{nm}: i=2.5 mmi = 2.5\,\mathrm{mm} — a ruler measures the wavelength of light. In a medium of index nn the path difference to use is the optical path n×n \times length, since λ=λ0/n\lambda = \lambda_0/n.

在原文中阅读 →