Biology · Glossary

What is pH, acid, base, pKa?

Also known as: pH · acid · pKa · base

Definition 8.7 University Biology — Year 1 · Chapter 8 — Water and Small Biomolecules

Water dissociates slightly, H2OH++OH\mathrm{H_2O} \rightleftharpoons \mathrm{H^+} + \mathrm{OH^-}, with [H+][OH]=Kw=1014mol2/L2[\mathrm{H^+}][\mathrm{OH^-}] = K_w = 10^{-14}\,\mathrm{mol}^{2}/\mathrm{L}^{2} at 25C25\,{}^{\circ}\mathrm{C}. The pH is log10[H+]-\log_{10}[\mathrm{H^+}]: 7 for pure water, lower for acids, higher for bases. An acid HA\mathrm{HA} releases a proton, HAH++A\mathrm{HA} \rightleftharpoons \mathrm{H^+} + \mathrm{A^-}, with dissociation constant Ka=[H+][A]/[HA]K_a = [\mathrm{H^+}][\mathrm{A^-}]/[\mathrm{HA}] and pKaK_a =log10Ka= -\log_{10}K_a; its conjugate base A\mathrm{A^-} accepts one. A strong acid (HCl) is fully dissociated; the acids of the cell (carboxylic acids, phosphates, ammonium) are weak, with pKaK_a between 2 and 10.

Examples

Example 8.6 (Melting a double helix)

The two strands of DNA are held by two or three hydrogen bonds per base pair plus the stacking (van der Waals) of neighbouring pairs; a single pair would separate at once, but a thousand pairs in a row hold until the temperature reaches about 90C90\,{}^{\circ}\mathrm{C}, and reunite, in exactly the same register, when it is lowered (Chapter 11). Specific, strong in number, reversible.

Example 8.11 (Blood)

Arterial blood holds 24mmol/L24\,\mathrm{mmol}/\mathrm{L} of bicarbonate and dissolved CO2\mathrm{CO_2} at 1.2mmol/L1.2\,\mathrm{mmol}/\mathrm{L} (set by the lungs): pH=6.1+log(24/1.2)=6.1+1.30=7.4\mathrm{pH} = 6.1 + \log(24/1.2) = 6.1 + 1.30 = 7.4. Adding 5mmol/L5\,\mathrm{mmol}/\mathrm{L} of acid turns 5mmol/L5\,\mathrm{mmol}/\mathrm{L} of bicarbonate into CO2\mathrm{CO_2}; if the lungs blow that CO2\mathrm{CO_2} off and hold the dissolved value, the pH becomes 6.1+log(19/1.2)=7.306.1 + \log(19/1.2) = 7.30; in a closed flask the CO2\mathrm{CO_2} would rise to 6.2mmol/L6.2\,\mathrm{mmol}/\mathrm{L} and the pH fall to 6.1+log(19/6.2)=6.596.1 + \log(19/6.2) = 6.59. The lungs make the difference.

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