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Mathematics · 术语表

什么是 Regular parametrized surface?

又称: parametrized surface

Definition 19.1 University Mathematics — Year 2 · 第 19 章 — Surfaces

Let U⊆R2U \subseteq \R^2 be open. A parametrized surface of class Ck\mathcal{C}^k (k≥1k \geq 1) is a map σ ⁣:U→R3\sigma \colon U \to \R^3, (u,v)↦σ(u,v)(u, v) \mapsto \sigma(u, v), of class Ck\mathcal{C}^k. A point is regular if the partial derivative vectors

σu(u,v)=∂σ∂u(u,v),σv(u,v)=∂σ∂v(u,v)\sigma_u(u, v) = \frac{\partial\sigma}{\partial u}(u,v), \qquad \sigma_v(u, v) = \frac{\partial\sigma}{\partial v}(u,v)

are linearly independent, i.e. σu∧σv≠0\sigma_u \wedge \sigma_v \neq 0; the surface is regular if every point is.

示例

Example 19.2 (The three standard descriptions)

  1. Graph: σ(u,v)=(u, v, f(u,v))\sigma(u, v) = (u,\ v,\ f(u, v)) for f∈C1(U)f \in \mathcal{C}^1(U). Always regular: σu=(1,0,fu)\sigma_u = (1, 0, f_u) and σv=(0,1,fv)\sigma_v = (0, 1, f_v) are independent.
  2. Sphere (spherical coordinates): for the sphere of radius RR,

    σ(θ,φ)=(Rcos⁡θcos⁡φ, Rsin⁡θcos⁡φ, Rsin⁡φ),(θ,φ)∈R×(−π2,π2),\sigma(\theta, \varphi) = (R\cos\theta\cos\varphi,\ R\sin\theta\cos\varphi,\ R\sin\varphi), \qquad (\theta, \varphi) \in \R \times \bigl(-\tfrac\pi2, \tfrac\pi2\bigr),

    with θ\theta the longitude and φ\varphi the latitude. One checks ∥σθ∧σφ∥=R2cos⁡φ>0\norm{\sigma_\theta \wedge \sigma_\varphi} = R^2\cos\varphi > 0: regular away from the poles (which this chart omits).

  3. Level set: S={(x,y,z):f(x,y,z)=c}S = \{(x,y,z) : f(x, y, z) = c\} where ff is C1\mathcal{C}^1 and ∇f≠0\nabla f \neq 0 on SS. Near each point, one coordinate can be expressed as a function of the other two by the implicit function theorem (Chapter 15), so SS is locally a graph.

Example 19.3 (From level set to graph)

The implicit function theorem in item 3 deserves one explicit run. Take the sphere x2+y2+z2=R2x^2 + y^2 + z^2 = R^2 near its north pole (0,0,R)(0, 0, R): there ∂f∂z=2z=2R≠0\frac{\partial f}{\partial z} = 2z = 2R \neq 0, and solving for zz gives the graph chart

z=R2−x2−y2,x2+y2<R2,z = \sqrt{R^2 - x^2 - y^2}, \qquad x^2 + y^2 < R^2 ,

regular everywhere on its (open) domain — including the pole that the spherical chart missed. Near an equator point like (R,0,0)(R, 0, 0) the same theorem solves for xx instead (∂f∂x=2R≠0\frac{\partial f}{\partial x} = 2R \neq 0). The rule of thumb: a level surface is a graph over the coordinate plane orthogonal to the largest component of the gradient, and by covering the sphere with six such graph charts one checks its smoothness everywhere with no trigonometry at all.

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