Physics · Glossary

What is Apparent weight?

Definition 25.13 High School Physics · Chapter 25 — Newton’s Laws

The apparent weight of a body is the normal force between it and its support — what a scale under it reads.

Two blocks, one light rope, one ideal pulley: the same tension T pulls both ends, the blocks share one magnitude of acceleration — one second law each, two equations, two unknowns.
Two blocks, one light rope, one ideal pulley: the same tension TT pulls both ends, the blocks share one magnitude of acceleration — one second law each, two equations, two unknowns.
A car in a flat curve at constant speed: from above (left) the velocity is tangent and the net force aims at the center; from behind (right) N balances P, and the sideways static friction of the road is the entire centripetal force. A car in a flat curve at constant speed: from above (left) the velocity is tangent and the net force aims at the center; from behind (right) N balances P, and the sideways static friction of the road is the entire centripetal force.
A car in a flat curve at constant speed: from above (left) the velocity is tangent and the net force aims at the center; from behind (right) N\vect N balances P\vect P, and the sideways static friction of the road is the entire centripetal force.

Examples

Example 25.14 (The elevator)

A 70kg70\,\mathrm{kg} passenger stands on a scale in an elevator of vertical acceleration aza_z (upward positive): Nmg=mazN - mg = ma_z, so N=m(g+az)N = m(g + a_z). Pulling up at az=1.5m/s2a_z = 1.5\,\mathrm{m}/\mathrm{s}^{2}: 792N792\,\mathrm{N}, heavy; braking near the top: 582N582\,\mathrm{N}, light; steady cruise: mg=687Nmg = 687\,\mathrm{N} — the first law; free fall, az=ga_z = -g: N=0N = 0, weightlessness on a scale.

Example 25.15 (Two blocks and a pulley)

A block m1=4.0kgm_1 = 4.0\,\mathrm{kg} on a frictionless table is tied by a light rope, over an ideal pulley, to a hanging block m2=1.0kgm_2 = 1.0\,\mathrm{kg}. The rope transmits the same tension TT at both ends; the blocks share one magnitude of acceleration aa. One second law each, along each motion: m1a=Tm_1 a = T and m2a=m2gTm_2 a = m_2 g - T, so a=m2g/(m1+m2)=1.96m/s2a = m_2\,g/(m_1 + m_2) = 1.96\,\mathrm{m}/\mathrm{s}^{2} and T=m1a=7.8NT = m_1 a = 7.8\,\mathrm{N} — smaller than m2g=9.8Nm_2 g = 9.8\,\mathrm{N}, as it must be for m2m_2 to accelerate downward.

Example 25.16 (The flat curve)

A car of mass mm rounds a flat curve of radius RR at constant speed vv. In the Frenet frame (Chapter 24) the acceleration is purely normal, aN=v2/Ra_N = v^2/R, aimed at the center. Vertically, N=mgN = mg; horizontally, the only centripetal force on offer is the static friction of road on tyres: f=mv2/RμsN=μsmgf = mv^2/R \leq \mu_s N = \mu_s mg, so vμsgRv \leq \sqrt{\mu_s\, g R}, whatever the mass. For R=90mR = 90\,\mathrm{m}, dry road (μs=0.70\mu_s = 0.70): vmax25m/sv_{\max} \approx 25\,\mathrm{m}/\mathrm{s} (89km/h89\,\mathrm{km}/\mathrm{h}); on ice the ceiling collapses — Exercise 25.13 banks the road; Exercise 25.10 swings the same projection on a wire.

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