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Mathematics · 术语表

什么是 compact operator?

Definition 15.1 University Mathematics — Year 3 · 第 15 章 — Compact Operators and the Spectral Theorem

T∈L(E,F)T \in \mathcal L(E, F) (E,FE, F Banach) is compact if the image T(B)T(B) of the unit ball is relatively compact in FF — equivalently, every bounded sequence (xn)(x_n) has a subsequence with (Txnk)(Tx_{n_k}) convergent. Finite-rank operators are compact (bounded sets in finite dimension); the identity of an infinite-dimensional space never is (Riesz’s theorem, Year 2).

示例

Example 15.3

(a) Diagonal operators on ℓ2\ell^2: T(xn)=(λnxn)T(x_n) = (\lambda_nx_n) is compact iff λn→0\lambda_n \to 0 (Exercise 15.2). (b) Kernel operators on C([0, 1])\mathcal C(\intcc01): compact by Ascoli (Exercise 7.7). (c) Hilbert–Schmidt operators: for k∈L2([0, 1]2)k \in L^2(\intcc01^2),

(Tkf)(x)=∫01k(x,y) f(y)  ⁣dy(T_kf)(x) = \int_0^1k(x, y)\,f(y)\,\dd y

defines a compact operator on L2([0, 1])L^2(\intcc01) with ∣∣∣Tk∣∣∣≤∥k∥L2\vertiii{T_k} \leq \norm k_{L^2} (Exercise 15.4: truncating the basis expansion of kk exhibits TkT_k as a limit of finite-rank operators).

Example 15.9

On L2([0, 1])L^2(\intcc01), let Tf(x)=∫01min⁡(x,y)f(y) ⁣dyTf(x) = \int_0^1\min(x, y)f(y)\dd y: a Hilbert–Schmidt operator with real symmetric kernel: compact and self-adjoint. Solving Tf=λfTf = \lambda f: the relation (Tf)(x)=∫0xyf(y) ⁣dy+x∫x1f(y) ⁣dy\bigl(Tf\bigr)(x) = \int_0^xyf(y)\dd y + x\int_x^1f(y)\dd y shows u=Tfu = Tf satisfies u′′=−fu'' = -f (two differentiations, legitimate for continuous ff, and TfTf is continuous for f∈L2f \in L^2: dominated convergence), with u(0)=0u(0) = 0 and u′(1)=0u'(1) = 0. So eigenfunctions solve λu′′=−u\lambda u'' = -u, u(0)=0u(0) = 0, u′(1)=0u'(1) = 0:

un(x)=sin⁡((n+12)πx),λn=1(n+12)2π2(n≥0),u_n(x) = \sin\Bigl(\bigl(n + \tfrac12\bigr)\pi x\Bigr), \qquad \lambda_n = \frac{1}{\bigl(n + \frac12\bigr)^2\pi^2} \quad (n \geq 0),

and the spectral theorem asserts — with no Fourier theory — that these sines form an orthonormal basis of L2([0, 1])L^2(\intcc01) after normalization (the kernel of TT is 00: Tf=0Tf = 0 forces, by the two differentiations, f=0f = 0 a.e.). The weekend problem runs the same circle of ideas for the vibrating string and extracts ζ(2)\zeta(2) from the trace.

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