Mathematics · Glossary

What is Mean?

Definition 8.3 High School Mathematics · Chapter 8 — Descriptive Statistics

The mean of the series is

xˉ=x1+x2++xNN.\bar x = \frac{x_1 + x_2 + \dots + x_N}{N}.

If the values v1,,vkv_1, \dots, v_k appear with counts n1,,nkn_1, \dots, n_k, the same number is computed as the weighted mean

xˉ=n1v1+n2v2++nkvkn1+n2++nk.\bar x = \frac{n_1 v_1 + n_2 v_2 + \dots + n_k v_k}{n_1 + n_2 + \dots + n_k}.

Examples

Example 8.4

For the quiz of Example 8.2:

xˉ=1×0+2×1+4×2+6×3+5×4+2×520=0+2+8+18+20+1020=5820=2.9.\bar x = \frac{1 \times 0 + 2 \times 1 + 4 \times 2 + 6 \times 3 + 5 \times 4 + 2 \times 5}{20} = \frac{0 + 2 + 8 + 18 + 20 + 10}{20} = \frac{58}{20} = 2.9 .

Example 8.6

Sorted series of 77 house prices (in thousands): 120120, 150150, 160160, 180180, 210210, 240240, 900900. The median is the 44th value, 180180. The mean is 19607=280\frac{1960}{7} = 280 — larger than 66 of the 77 prices! One extreme value (900900) pulls the mean far more than the median: the median is robust, the mean is not.

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Definition 17.1 High School Mathematics · Chapter 17 — Descriptive Statistics

The mean of the values x1,x2,,xnx_1, x_2, \dots, x_n is

xˉ=x1+x2++xnn.\bar x = \frac{x_1 + x_2 + \dots + x_n}{n}.

If the value xix_i appears with frequency nin_i (with n1++nk=nn_1 + \dots + n_k = n), then xˉ=n1x1++nkxkn\bar x = \frac{n_1 x_1 + \dots + n_k x_k}{n}.

Examples

Example 17.3

For the running dataset, the sum is 144144, so xˉ=14412=12\bar x = \frac{144}{12} = 12. The two middle values (66th and 77th of the sorted list) are both 1212, so the median is 1212 too. Mean and median need not coincide: the median ignores how far the extreme values are, the mean does not. Replacing the top mark 1717 by 2020 moves the mean to 12.2512.25 but leaves the median at 1212.

Example 17.8

For the running dataset, the deviations from xˉ=12\bar x = 12 are 4-4, 3-3, 2-2, 2-2, 1-1, 00, 00, 00, 11, 22, 44, 55; their squares sum to

16+9+4+4+1+0+0+0+1+4+16+25=80.16 + 9 + 4 + 4 + 1 + 0 + 0 + 0 + 1 + 4 + 16 + 25 = 80 .

Hence

V=8012=2036.67,σ=20/32.6 marks.V = \frac{80}{12} = \frac{20}{3} \approx 6.67, \qquad \sigma = \sqrt{20/3} \approx 2.6 \text{ marks}.

Roughly speaking, a typical mark sits about 2.62.6 marks away from the mean.

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