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Mathematics · পরিভাষা

Subspace কী?

Definition 18.3 University Mathematics — Year 1 · অধ্যায় 18 — Vector Spaces

F⊆EF \subseteq E is a subspace when 0E∈F0_E \in F and FF is stable under addition and scalar multiplication — equivalently:

F≠∅and∀x,y∈F, ∀λ∈K,x+λy∈F.F \neq \emptyset \qquad\text{and}\qquad \forall x, y \in F,\ \forall \lambda \in K,\quad x + \lambda y \in F .

A subspace is itself a vector space. Any intersection of subspaces is a subspace; a union almost never is (same proof as Exercise 7.6).

উদাহরণ

Example 18.4

In F(R,R)\mathcal{F}(\R, \R): the continuous functions, the differentiable ones, the polynomials of degree ≤n\leq n (written Kn[X]K_n[X] inside K[X]K[X]), the solutions of a homogeneous linear differential equation (Theorem 5.10 said just that). Non-examples: {f:f(0)=1}\{f : f(0) = 1\} (no zero), degree exactly nn (not stable under addition).

Example 18.5 (Subspace or not: four verdicts, argued)

In the space of real sequences:

  • {u:u bounded}\{u : u \text{ bounded}\} is a subspace: 00 is bounded, and if ∣un∣≤M\abs{u_n} \leq M, ∣vn∣≤M′\abs{v_n} \leq M', then ∣un+λvn∣≤M+∣λ∣M′\abs{u_n + \lambda v_n} \leq M + \abs\lambda M'.
  • {u:un→1}\{u : u_n \to 1\} is not: the zero sequence is missing (and the sum of two members tends to 22).
  • {u:u monotone}\{u : u \text{ monotone}\} is not: un=nu_n = n and vn=−n+(−1)nv_n = -n + (-1)^n are monotone, their sum (−1)n(-1)^n is not; stability under addition is the axiom that fails, even though the set contains 00 and all scalar multiples of its members.
  • {u:un+1=un2}\{u : u_{n+1} = u_n^2\} is not: it contains 00 but 2u2u escapes as soon as uu is a nonzero member (2un+1≠(2un)22u_{n+1} \neq (2u_n)^2 in general) — squaring is the nonlinearity.

The working order is always the same: test 00 first (cheapest), then stability — and to refute, one explicit counterexample pair beats any amount of doubt.

Example 18.12 (A supplementary pair in Kn[X]K_n[X])

Fix a∈Ka \in K and set F={P∈Kn[X]:P(a)=0}F = \{P \in K_n[X] : P(a) = 0\}, G=Vect⁡(1)G = \operatorname{Vect}(1) (the constants). Then Kn[X]=F⊕GK_n[X] = F \oplus G. Indeed F∩GF \cap G consists of the constants vanishing at aa, i.e. {0}\{0\}; and every PP decomposes as

P=(P−P(a))⏟∈F+P(a)⏟∈G.P = \underbrace{\bigl(P - P(a)\bigr)}_{\in F} + \underbrace{P(a)}_{\in G} .

The decomposition is worth memorizing: subtracting the value at a point is the standard way to project onto “functions vanishing at aa”. Note that FF is a large subspace and GG a small one; a supplementary pair need not be balanced in any sense.

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