Mathematics · Glossary

What is Continuity?

Also known as: continuous

Definition 21.9 High School Mathematics · Chapter 21 — Limits and Continuity

Let ff be defined on an interval II and aIa \in I. The function ff is continuous at aa if limxaf(x)=f(a)\lim\limits_{x \to a} f(x) = f(a). It is continuous on II if it is continuous at every point of II.

Examples

Example 21.17

The equation x3+x=1x^3 + x = 1 has a unique real solution. Indeed f(x)=x3+xf(x) = x^3 + x is continuous and strictly increasing on R\R (as a sum of strictly increasing functions), limf=\lim_{-\infty} f = -\infty and lim+f=+\lim_{+\infty} f = +\infty, so the bijection theorem applies with k=1k = 1. Since f(0.6)=0.816<1f(0.6) = 0.816 < 1 and f(0.7)=1.043>1f(0.7) = 1.043 > 1, the solution lies in (0.6,0.7)\intoo{0.6}{0.7}.

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Definition 13.6 University Mathematics — Year 1 · Chapter 13 — Limits and Continuity

ff is continuous at x0Ix_0 \in I when f(x)f(x0)f(x) \to f(x_0) as xx0x \to x_0; continuous on II when it is continuous at every point. By Theorem 13.3: ff is continuous at x0x_0 iff f(un)f(x0)f(u_n) \to f(x_0) for every sequence unx0u_n \to x_0 in II.

A continuous function with f(a) < 0 < f(b) must cross the axis: the dichotomy proof of  traps a crossing point between adjacent sequences.
A continuous function with f(a)<0<f(b)f(a) < 0 < f(b) must cross the axis: the dichotomy proof of Theorem 13.10 traps a crossing point between adjacent sequences.

Examples

Example 13.7 (A taxonomy of discontinuities)

Three ways to fail at a point, in increasing severity. Removable: f(x)=sinxxf(x) = \frac{\sin x}{x} on R\R^* has limit 11 at 00; defining f(0)=1f(0) = 1 repairs it — the discontinuity was a hole, not a feature. Jump: x\lfloor x \rfloor at an integer has distinct one-sided limits (n1n - 1 and nn); no choice of value can reconcile them, but both half-limits exist. Essential: sin1x\sin\frac1x at 00 has no one-sided limit at all (Exercise 13.1) — oscillation without settlement. Monotone functions can only produce the middle kind (their one-sided limits always exist, being suprema and infima), which is why their discontinuity sets are at most countable — one rational per jump. Derivatives, by Darboux’s theorem (Exercise 14.10), can only produce the last kind: a function with a jump discontinuity is never the derivative of anything.

Example 13.9 (Max and min of continuous functions)

If f,gf, g are continuous, so are max(f,g)\max(f, g) and min(f,g)\min(f, g): no case analysis needed, thanks to the identities

max(f,g)=f+g+fg2,min(f,g)=f+gfg2,\max(f, g) = \frac{f + g + \abs{f - g}}{2}, \qquad \min(f, g) = \frac{f + g - \abs{f - g}}{2},

and the continuity of sums and of \abs{\,\cdot\,} (Proposition 13.8). In particular f+=max(f,0)f^+ = \max(f, 0) and f=max(f,0)f^- = \max(-f, 0) are continuous with f=f+ff = f^+ - f^-: the sign-splitting used for series (Chapter 17) and, at full scale, in the integration theory of the Year 3 volume, costs nothing in regularity.

Example 13.11 (One equation, the full protocol)

Solve ex=3x\eu^x = 3 - x over R\R: existence, uniqueness, location. Set g(x)=ex+x3g(x) = \eu^x + x - 3, continuous. Location and existence: g(0)=2<0g(0) = -2 < 0 and g(1)=e2>0g(1) = \eu - 2 > 0, so the intermediate value theorem plants a solution in (0,1)\intoo{0}{1}. Uniqueness: gg is a sum of the strictly increasing ex\eu^x and x3x - 3, hence strictly increasing on R\R; a strictly monotone function takes each value at most once, so the solution is unique on all of R\R (not just in the interval probed). The protocol — rearrange to g=0g = 0, sign change for existence, monotonicity for uniqueness — settles most “how many solutions” questions in three lines, and Chapter 14’s variation tables extend it to non-monotone gg by cutting R\R into monotone branches.

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