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Matemática · পরিভাষা

Formas exatas e fechadas কী?

অন্য নাম: forma exata · potencial · forma fechada

Definição 20.5 Matemática universitária — Graduação 2 · অধ্যায় 20 — Integrais de linha e integrais múltiplas

A forma ω=P  ⁣dx+Q  ⁣dy\omega = P\,\dd x + Q\,\dd y de classe C0\mathcal{C}^0 é exata em UU se existe f∈C1(U)f \in \mathcal{C}^1(U) (um potencial) com ω= ⁣df\omega = \dd f, isto é, P=fxP = f_x e Q=fyQ = f_y. Uma forma C1\mathcal{C}^1 é fechada se Py=QxP_y = Q_x em UU.

উদাহরণ

Exemplo 20.7 (Reconstruindo um potencial)

Seja ω=y exy  ⁣dx+(x exy+2y)  ⁣dy\omega = y\,\eu^{xy}\,\dd x + (x\,\eu^{xy} + 2y)\,\dd y em R2\R^2. Ela é fechada: ambas as derivadas cruzadas valem exy(1+xy)\eu^{xy}(1 + xy). Para achar um potencial, integre PP em xx com yy fixo:

f(x,y)=∫y exy  ⁣dx=exy+c(y),f(x, y) = \int y\,\eu^{xy}\,\dd x = \eu^{xy} + c(y),

depois ajuste cc igualando fyf_y: x exy+c′(y)=x exy+2yx\,\eu^{xy} + c'(y) = x\,\eu^{xy} + 2y dá c(y)=y2c(y) = y^2. Assim f(x,y)=exy+y2f(x,y) = \eu^{xy} + y^2 e, para qualquer arco C1\mathcal C^1 por pedaços de (0,0)(0,0) a (1,1)(1,1),

∫γω=f(1,1)−f(0,0)=(e+1)−1=e,\int_\gamma\omega = f(1,1) - f(0,0) = (\eu + 1) - 1 = \eu ,

independentemente do caminho — a receita em dois passos (integrar em xx, corrigir em yy) é a recíproca prática do Teorema 20.6 em domínios em que as formas fechadas são exatas.

Exemplo 20.8 (Fechada não implica exata)

Em U=R2∖{0}U = \R^2 \setminus \{0\}, a forma ângulo

ω=−y  ⁣dx+x  ⁣dyx2+y2\omega = \frac{-y\,\dd x + x\,\dd y}{x^2 + y^2}

é fechada (cálculo direto: tanto PyP_y quanto QxQ_x valem y2−x2(x2+y2)2\frac{y^2 - x^2}{(x^2+y^2)^2}), mas sua integral ao longo do círculo unitário vale 2π≠02\pi \neq 0 (mesmo cálculo do Exemplo 20.3, dividido por 11): ω\omega não é exata em UU. Localmente, ω= ⁣dθ\omega = \dd\theta para uma determinação θ\theta do ângulo polar; a falha é global — o ângulo não pode ser definido continuamente em torno do furo. Em domínios sem buracos a patologia desaparece: num aberto estrelado, toda forma C1\mathcal{C}^1 fechada é exata (lema de Poincaré, Exercício 20.8).

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