Biology · Book 4 · Bachelor Year 2

University Biology — Year 2

University Biology — Year 2 · Bachelor Year 2

16Blood and the Circulatory System

In 1628 William Harvey did a sum. The heart, he estimated, holds about two ounces of blood and beats seventy times a minute; even if only a fraction of that were expelled at each beat, the heart would pump in an hour several times the weight of the whole body. The blood could not be made and consumed at that rate, as Galen had taught for fourteen centuries; it must go round and round. Then he showed it: tie a cord round the arm, and the veins below the cord swell, not above; press the blood in a vein toward the hand, past a valve, and it will not go. The blood is pumped out through the arteries, returns through the veins, and the whole five litres pass through the heart every minute. This chapter is about that closed system — what the blood is, how it is routed, the physics of its flow through vessels from the aorta to a capillary, and the exchange, in the capillaries, that is the point of all of it.

16.1 Blood

Definition 16.1 (The composition of blood)

Blood is a tissue in suspension: about 5L5\,\mathrm{L} in an adult, 7%7\,\% of body mass. Spun down, it separates into plasma (55%55\,\%: water, 70g/L70\,\mathrm{g}/\mathrm{L} of proteins — albumin, globulins, fibrinogen — and the salts, sugars, lipids, gases and hormones it carries) and cells (45%45\,\%, the haematocrit): red cells (5×10125\times 10^{12} per litre, biconcave discs of 7µm7\,\text{µ}\mathrm{m} without a nucleus, each packed with 280280 million molecules of haemoglobin, living 120 days and made in the marrow at two million a second), white cells (7×1097\times 10^{9} per litre: neutrophils, lymphocytes, monocytes, eosinophils, basophils, the mobile arm of immunity), and platelets (3×10113\times 10^{11} per litre, fragments of marrow cells that plug wounds and start clotting). The red cells carry oxygen — 200mL200\,\mathrm{mL} per litre of blood at full saturation, seventy times what water dissolves — and the plasma carries everything else, including the 20%20\,\% of CO2\mathrm{CO_2} that is not in the cells, the heat of the muscles to the skin, and the hormones of Chapter 19 to their targets. Blood is also a solution under oncotic pressure: its proteins, which cannot leave the capillaries, hold about 25mmHg25\,\mathrm{mmHg} of osmotic pull, and that pull is what keeps the plasma in the vessels.

A red cell, a platelet and a white cell (a lymphocyte) under the scanning electron microscope: the three cellular components of blood, drawn to the same scale.
A red cell, a platelet and a white cell (a lymphocyte) under the scanning electron microscope: the three cellular components of blood, drawn to the same scale.

Proposition 16.2 (Haemostasis)

A cut vessel is sealed in three steps within minutes. The vessel constricts; platelets stick to the exposed collagen, release signals that recruit and activate more platelets, and form a plug; and a cascade of plasma proteases, each activating the next (a dozen clotting factors, most made in the liver, several needing vitamin K), converts fibrinogen into insoluble fibrin, whose threads mesh the plug into a clot. A cascade amplifies: a trace of the trigger (tissue factor from the damaged wall) ends in grams of fibrin. It must also be contained: anticoagulants in the plasma (antithrombin, protein C) and on the intact endothelium confine the clot to the wound, and a second system, fibrinolysis, dissolves it as the vessel heals. Haemophilia is the lack of one factor; a thrombosis is a clot where none was wanted, and the leading cause of death in rich countries is a clot in a coronary or cerebral artery.

16.2 Circuits

Definition 16.3 (Open and closed, single and double)

In an open circulation (insects, most molluscs) a heart pumps blood into a body cavity where it bathes the organs directly and returns at low pressure; flow is slow and poorly directed, and the insects have separated the gas problem from the blood by piping air straight to the tissues. In a closed circulation (annelids, cephalopods, vertebrates) the blood stays in vessels and is driven through capillaries at pressure, so that its distribution can be controlled organ by organ. Fish have a single circuit: heart \to gills \to body \to heart, so that blood reaches the tissues at the low pressure left after the gill capillaries. Mammals and birds have a double circuit: the right heart drives the pulmonary circulation (lungs, low pressure, 25mmHg25\,\mathrm{mmHg} systolic) and the left heart, after the blood returns, drives the systemic circulation (body, high pressure, 120mmHg120\,\mathrm{mmHg}); the two pumps are in series and move the same flow, about 5L5\,\mathrm{L} a minute at rest. Amphibians and most reptiles have a heart with a single ventricle that partly mixes the two streams — the intermediate stage. The double circuit is what makes a warm-blooded metabolism possible: high pressure to every organ and a lung protected from it.

Evidence. Harvey (1628) argued from quantity — the output computed above — and from structure: the valves in the veins, which Fabricius had described, allow flow only toward the heart, as he showed by pressing on the veins of a ligatured arm; the valves of the heart allow flow only from atria to ventricles to arteries; and blood in the arteries spurts, in the veins seeps. He could not see the capillaries and inferred them; Malpighi saw them in a frog’s lung in 1661, four years after Harvey’s death.

William Harvey, and the plate from his book of 1628: the veins of a ligatured forearm swell below the cord, and blood pressed toward the hand stops at the valves. William Harvey, and the plate from his book of 1628: the veins of a ligatured forearm swell below the cord, and blood pressed toward the hand stops at the valves.
William Harvey, and the plate from his book of 1628: the veins of a ligatured forearm swell below the cord, and blood pressed toward the hand stops at the valves.
The double circulation. The right heart sends blood through the lungs at low pressure; the left heart sends it round the body at high pressure; the two pumps, in series, move the same volume per minute.
The double circulation. The right heart sends blood through the lungs at low pressure; the left heart sends it round the body at high pressure; the two pumps, in series, move the same volume per minute.

16.3 Vessels and the physics of flow

Definition 16.4 (The vascular tree)

Blood leaves the heart through arteries: thick-walled tubes with elastic layers that stretch at each beat and recoil between beats, smoothing the pulses into a steadier flow (the aorta is 2.5cm2.5\,\mathrm{cm} across). They branch into arterioles, vessels of a tenth of a millimetre or less whose walls are mostly smooth muscle: by contracting or relaxing, an arteriole changes its radius and so, powerfully, its resistance — arterioles are the taps of the circulation and the site of most of the pressure drop. These open into capillaries: tubes of a single endothelial cell wrapped round a lumen of 5 to 10µm5\text{ to }10\,\text{µ}\mathrm{m}, about 1mm1\,\mathrm{mm} long, some forty billion of them with a total surface near 600m2600\,\mathrm{m}^{2}, across whose walls all exchange takes place. Capillaries drain into venules and veins: thin-walled, distensible, holding two thirds of the blood at low pressure, with valves that keep the flow toward the heart while muscles squeeze them. Every vessel is lined with a single layer of endothelium, which is not a passive lining but a gland — it releases nitric oxide to relax the arteriole, and signals that recruit white cells — and a filter.

A capillary bed: an arteriole feeding a mesh of capillaries in which red cells travel in single file, rejoining into a venule.
A capillary bed: an arteriole feeding a mesh of capillaries in which red cells travel in single file, rejoining into a venule.

Theorem 16.5 (Poiseuille’s law and vascular resistance)

The steady flow QQ of a fluid of viscosity η\eta through a tube of radius rr and length LL under a pressure difference ΔP\Delta P is

Q=πr48ηLΔP,so thatRΔPQ=8ηLπr4.Q = \frac{\pi r^{4}}{8\eta L}\,\Delta P, \qquad \text{so that}\qquad R \equiv \frac{\Delta P}{Q} = \frac{8\eta L}{\pi r^{4}} .

The resistance falls as the fourth power of the radius: an arteriole that narrows its radius by 20%20\,\% multiplies its resistance by 1/0.84=2.41/0.8^{4} = 2.4, and one that halves it by 16. This is why a few millimetres of arteriolar muscle can redirect the blood of the whole body — to the gut after a meal, to the muscles in exercise, to the skin in heat — and why the pressure falls from 95mmHg95\,\mathrm{mmHg} in the small arteries to 35mmHg35\,\mathrm{mmHg} at the entrance of the capillaries, almost all of it across the arterioles, while the drop along the aorta is a fraction of a millimetre of mercury.

Proof. In steady laminar flow the fluid moves in concentric shells; the viscous force between shells balances the pressure. For the cylinder of radius s<rs < r the pressure force πs2ΔP\pi s^{2}\Delta P equals the viscous drag on its surface 2πsLη(dv/ds)2\pi s L\,\eta\,(-\mathrm{d}v/ \mathrm{d}s), so dv/ds=sΔP/(2ηL)\mathrm{d}v/\mathrm{d}s = -s\Delta P/(2\eta L) and, with v(r)=0v(r) = 0, v(s)=(ΔP/4ηL)(r2s2)v(s) = (\Delta P/4\eta L)(r^{2} - s^{2}) — a parabolic profile. Integrating the velocity over the cross-section, Q=0rv2πsds=(πΔP/2ηL)0r(r2ss3)ds=πr4ΔP/8ηLQ = \int_{0}^{r} v\,2\pi s\,\mathrm{d}s = (\pi\Delta P/2\eta L) \int_{0}^{r}(r^{2}s - s^{3})\,\mathrm{d}s = \pi r^{4}\Delta P/8\eta L. (Blood is not quite a simple fluid and arteries are not rigid, but the fourth-power law holds well enough to run a body.)

Theorem 16.6 (Continuity: where the blood slows down)

The same volume per second passes every level of the tree, so the mean velocity at a level is v=Q/Av = Q/A, where AA is the total cross-sectional area of all the vessels at that level. The aorta (3cm23\,\mathrm{cm}^{2}) carries 5L/min5\,\mathrm{L}/\mathrm{min} at 28cm/s28\,\mathrm{cm}/\mathrm{s}; the capillaries, with a total cross-section near 3000cm23000\,\mathrm{cm}^{2}, carry it at 0.03cm/s0.03\,\mathrm{cm}/\mathrm{s}, so that a red cell takes some three seconds to cross a capillary — time enough for its oxygen to diffuse out (Chapter 1: a micrometre in a millisecond). The veins, of smaller total section than the capillaries, speed the blood up again to 10cm/s10\,\mathrm{cm}/\mathrm{s} in the venae cavae. The tree is built so that the blood is slow exactly where it must exchange and fast everywhere else.

Proof. Conservation of volume: what enters a level per second leaves it, so Q=AvQ = A\,v is the same at every level. 5L/min=83cm3/s5\,\mathrm{L}/\mathrm{min} = 83\,\mathrm{cm}^{3}/\mathrm{s}; 83/3=28cm/s83/3 = 28\,\mathrm{cm}/\mathrm{s}; 83/3000=0.028cm/s83/3000 = 0.028\,\mathrm{cm}/\mathrm{s}.

Pressure (red) and mean velocity (blue) along the systemic circulation. The pulse is smoothed in the arteries, the pressure falls mostly across the arterioles, and the blood is slowest in the capillaries, where the total cross-section is a thousand times that of the aorta.
Pressure (red) and mean velocity (blue) along the systemic circulation. The pulse is smoothed in the arteries, the pressure falls mostly across the arterioles, and the blood is slowest in the capillaries, where the total cross-section is a thousand times that of the aorta.

Theorem 16.7 (The elastic artery as a reservoir)

The heart ejects in bursts; the tissues receive a nearly steady flow. The large arteries do the smoothing: they stretch during ejection, storing part of the stroke volume, and recoil during diastole, driving it on. If the arteries have a compliance CC (volume stored per unit pressure) and the arterioles a resistance RR, then during diastole, with the aortic valve shut, the pressure decays as

P(t)=Pset/RC,P(t) = P_{s}\,e^{-t/RC},

so that the diastolic pressure after a diastole of duration tdt_d is Psetd/RCP_s e^{-t_d/RC}: with R=1mmHgs/mLR = 1\,\mathrm{mmHg}\,\mathrm{s}/\mathrm{mL}, C=2mL/mmHgC = 2\,\mathrm{mL}/\mathrm{mmHg} and td=0.8st_d = 0.8\,\mathrm{s}, a systolic 120mmHg120\,\mathrm{mmHg} falls to 80mmHg80\,\mathrm{mmHg}. A stiffer aorta (smaller CC, as in old age) lets the pressure fall further between beats and rise higher during ejection: the pulse pressure widens, and the heart works against a higher peak.

Proof. During diastole no blood enters the arteries and blood leaves them through the arterioles at Q=P/RQ = P/R; the arterial volume falls at dV/dt=P/R\mathrm{d}V/\mathrm{d}t = -P/R, and since dV=CdP\mathrm{d}V = C\, \mathrm{d}P, CdP/dt=P/RC\,\mathrm{d}P/\mathrm{d}t = -P/R, whose solution is the exponential with time constant RCRC. With RC=2sRC = 2\,\mathrm{s}: 120e0.4=80mmHg120\,e^{-0.4} = 80\,\mathrm{mmHg}.

16.4 Exchange in the capillaries

Proposition 16.8 (Two kinds of exchange)

Across the capillary wall, solutes move by diffusion — gases and lipids through the cells, water and small solutes through the clefts between them, over the enormous area and the short distance that make the flux ample (Fick’s law, as for the placenta of Chapter 8) — and water moves by bulk flow, driven by the balance of two pressures. The hydrostatic pressure in the capillary, PcP_c, pushes fluid out; the oncotic pressure of the plasma proteins, πc\pi_c, pulls it in (Starling forces). At the arterial end Pc35mmHgP_c \approx 35\,\mathrm{mmHg} exceeds πc25mmHg\pi_c \approx 25\,\mathrm{mmHg} and fluid filters out; at the venous end Pc15mmHgP_c \approx 15\,\mathrm{mmHg} and fluid is reabsorbed; over the whole body about 20L20\,\mathrm{L} a day filter out and 17L17\,\mathrm{L} return, and the balance of 3L3\,\mathrm{L}, with the proteins that leaked, is collected by the lymphatic vessels and returned to the veins at the neck. Oedema — swelling by fluid in the tissues — follows whenever the balance tips: high venous pressure (heart failure), low plasma protein (starvation, liver or kidney disease), leaky capillaries (inflammation), or blocked lymphatics.

Starling forces along a capillary. Hydrostatic pressure pushes fluid out and the plasma proteins’ oncotic pressure pulls it back; filtration at the arterial end exceeds reabsorption at the venous end, and the lymph returns the difference.
Starling forces along a capillary. Hydrostatic pressure pushes fluid out and the plasma proteins’ oncotic pressure pulls it back; filtration at the arterial end exceeds reabsorption at the venous end, and the lymph returns the difference.

Theorem 16.9 (Oncotic pressure)

A solution of cc moles per litre of a solute that cannot cross a membrane exerts across it an osmotic pressure π=cRT\pi = cRT (van ’t Hoff). Plasma albumin, 40g/L40\,\mathrm{g}/\mathrm{L} of a protein of molar mass 66kg/mol66\,\mathrm{kg}/\mathrm{mol}, is c=0.6mmol/Lc = 0.6\,\mathrm{mmol}/\mathrm{L} and gives π=0.6×8.314×310=1.55kPa12mmHg\pi = 0.6\times 8.314\times 310 = 1.55\,\mathrm{kPa} \approx 12\,\mathrm{mmHg}; the other proteins and the extra ions that albumin’s negative charge retains bring the total to about 25mmHg25\,\mathrm{mmHg}. The sodium chloride of plasma, at 150mmol/L150\,\mathrm{mmol}/\mathrm{L}, would exert 5800mmHg5800\,\mathrm{mmHg} — but it crosses the capillary wall freely and exerts none across it. What matters for the capillary is the protein: halve the albumin, as in kidney disease that loses it in the urine, and the reabsorbing pull halves, fluid accumulates in the tissues, and the patient swells.

Proof. 40g/L/66000g/mol=6.1×104mol/L=0.61mol/m340\,\mathrm{g}/\mathrm{L}/66\,000\,\mathrm{g}/\mathrm{mol} = 6.1 \times 10^{-4}\,\mathrm{mol}/\mathrm{L} = 0.61\,\mathrm{mol}/\mathrm{m}^{3}; π=cRT=0.61×8.314×310=1570Pa\pi = cRT = 0.61\times 8.314\times 310 = 1570\,\mathrm{Pa}; 1mmHg=133Pa1\,\mathrm{mmHg} = 133\,\mathrm{Pa}, so 11.8mmHg11.8\,\mathrm{mmHg}. The van ’t Hoff law itself is the dilute-solution limit derived in the Year 1 volume.

Example 16.10 (The circulation as a transport system)

Five litres a minute through 600m2600\,\mathrm{m}^{2} of capillary wall is a delivery service without equal. It brings each cell oxygen within a few cell diameters (no cell of the body is more than 20µm20\,\text{µ}\mathrm{m} from a capillary), removes its CO2\mathrm{CO_2}, lactate and urea, carries the glucose of the liver to the brain and the fatty acids of the fat stores to the muscles, distributes the hormones of Chapter 19 from one gland to every receptor in the body in a minute, moves the heat of the core to the skin and back, and ferries the white cells to a wound within hours. It is also the vulnerability: a clot, a haemorrhage or a failing pump stops all of it at once, and the brain, which stores no fuel, fails within seconds. The rest of this part of the book is about the pump (Chapter 17) and about how the pressure is regulated so that the service continues through standing up, running and bleeding (Chapter 18).

16.5 Exercises

Exercise 16.1

Give the composition of blood by volume and the number, size and function of each cellular component.

Solution

Solution of Exercise 16.1.

Plasma 55%55\,\% (water, 70g/L70\,\mathrm{g}/\mathrm{L} of protein, salts, nutrients, gases, hormones); cells 45%45\,\%. Red cells 5×10125\times 10^{12}/L, 7µm7\,\text{µ}\mathrm{m} discs, oxygen transport; white cells 7×1097\times 10^{9}/L, 10 to 15µm10\text{ to }15\,\text{µ}\mathrm{m}, immunity; platelets 3×10113\times 10^{11}/L, 2µm2\,\text{µ}\mathrm{m} fragments, haemostasis.

Exercise 16.2

Draw the circuit of a fish and of a mammal, mark the pressures, and say what the double circuit gains.

Solution

Solution of Exercise 16.2.

Fish: heart \to gills \to body \to heart, one circuit, the body receiving blood at the low pressure left after the gills. Mammal: right heart \to lungs (25mmHg25\,\mathrm{mmHg}) \to left heart \to body (120mmHg120\,\mathrm{mmHg}) \to right heart. The double circuit gives the body high pressure without exposing the lungs to it, and lets the two circuits be regulated separately.

Exercise 16.3

For each vessel type — artery, arteriole, capillary, vein — give the wall structure and the function it serves.

Solution

Solution of Exercise 16.3.

Artery: thick wall with elastic layers and muscle — conducts blood at high pressure and smooths the pulse. Arteriole: wall mostly smooth muscle — sets resistance and distributes flow. Capillary: one endothelial cell thick — exchange. Vein: thin, distensible wall with valves — returns blood at low pressure and stores most of it.

Exercise 16.4

Reconstruct Harvey’s argument from quantity, with modern numbers: 70mL70\,\mathrm{mL} per beat, 7272 beats a minute, 5L5\,\mathrm{L} of blood.

Solution

Solution of Exercise 16.4.

70×72=5L/min70\times 72 = 5\,\mathrm{L}/\mathrm{min}, 7200L7200\,\mathrm{L} a day, against 5L5\,\mathrm{L} of blood: the volume passes through the heart 14401440 times a day. No organ could make or consume seven tonnes of blood a day; the same blood must return — it circulates.

Exercise 16.5 ★★

Compute the pressure drop along the aorta (radius 1.25cm1.25\,\mathrm{cm}, length 40cm40\,\mathrm{cm}, η=3×103Pas\eta = 3 \times 10^{-3}\,\mathrm{Pa}\,\mathrm{s}) carrying 5L/min5\,\mathrm{L}/\mathrm{min} by Poiseuille’s law, in pascals and in mmHg. Comment.

Solution

Solution of Exercise 16.5.

ΔP=8ηLQ/πr4=8×3×103×0.4×8.3×105/(π×2.44×108)=10Pa\Delta P = 8\eta LQ/\pi r^{4} = 8\times 3\times 10^{-3}\times 0.4\times 8.3\times 10^{-5}/(\pi\times 2.44\times 10^{-8}) = 10\,\mathrm{Pa}, 0.08mmHg0.08\,\mathrm{mmHg}: the aorta costs nothing; the pressure is spent in the arterioles.

Exercise 16.6 ★★

An arteriole of radius 15µm15\,\text{µ}\mathrm{m} constricts to 12µm12\,\text{µ}\mathrm{m}, then dilates to 20µm20\,\text{µ}\mathrm{m}. By what factor does its resistance change in each case, and its flow at constant pressure?

Solution

Solution of Exercise 16.6.

(15/12)4=2.4(15/12)^{4} = 2.4: resistance up 2.4-fold, flow down to 41%41\,\%. (15/20)4=0.32(15/20)^{4} = 0.32: resistance down to a third, flow up 3.2-fold.

Exercise 16.7 ★★

The aorta has a cross-section of 3cm23\,\mathrm{cm}^{2} and the capillaries a total of 3000cm23000\,\mathrm{cm}^{2}; the flow is 5L/min5\,\mathrm{L}/\mathrm{min}. Compute the mean velocity in each, and the time a red cell spends in a 1mm1\,\mathrm{mm} capillary. During exercise the output rises to 25L/min25\,\mathrm{L}/\mathrm{min} and the muscle capillaries open: what happens to the transit time?

Solution

Solution of Exercise 16.7.

Aorta 83/3=28cm/s83/3 = 28\,\mathrm{cm}/\mathrm{s}; capillaries 83/3000=0.028cm/s83/3000 = 0.028\,\mathrm{cm}/\mathrm{s}; transit 0.1/0.028=3.6s0.1/0.028 = 3.6\,\mathrm{s}. In exercise the output rises fivefold and the open capillary area perhaps threefold, so the transit time falls to about 2s2\,\mathrm{s} — still enough for the oxygen to leave.

Exercise 16.8 ★★

With Pc=35P_c = 35 and 15mmHg15\,\mathrm{mmHg} at the two ends, πc=25mmHg\pi_c = 25\,\mathrm{mmHg}, interstitial pressures negligible, compute the net filtration pressure at each end. What happens if venous pressure rises so that PcP_c at the venous end is 28mmHg28\,\mathrm{mmHg}?

Solution

Solution of Exercise 16.8.

Arterial end 3525=+10mmHg35 - 25 = +10\,\mathrm{mmHg} (filtration); venous end 1525=10mmHg15 - 25 = -10\,\mathrm{mmHg} (reabsorption). With Pc=28P_c = 28 at the venous end the net is +3+3: fluid filters along the whole length and none is reabsorbed — oedema, the swollen ankles of heart failure.

Exercise 16.9 ★★

Compute the oncotic pressure of 40g/L40\,\mathrm{g}/\mathrm{L} of albumin (66kg/mol66\,\mathrm{kg}/\mathrm{mol}) at 37C37\,{}^{\circ}\mathrm{C}, and of 20g/L20\,\mathrm{g}/\mathrm{L}. Why does the sodium of plasma, at 150mmol/L150\,\mathrm{mmol}/\mathrm{L}, contribute nothing to the Starling balance?

Solution

Solution of Exercise 16.9.

40/66000=0.61mol/m340/66000 = 0.61\,\mathrm{mol}/\mathrm{m}^{3}; π=0.61×8.314×310=1570Pa=11.8mmHg\pi = 0.61\times 8.314\times 310 = 1570\,\mathrm{Pa} = 11.8\,\mathrm{mmHg}; half the albumin, 5.9mmHg5.9\,\mathrm{mmHg}. Sodium crosses the capillary wall freely, so its concentration is the same on both sides and it exerts no osmotic pressure across it.

Exercise 16.10 ★★★

With R=1mmHgs/mLR = 1\,\mathrm{mmHg}\,\mathrm{s}/\mathrm{mL} and C=2mL/mmHgC = 2\,\mathrm{mL}/\mathrm{mmHg}, compute the diastolic pressure after 0.8s0.8\,\mathrm{s} from a systolic of 120mmHg120\,\mathrm{mmHg}. Recompute for an aorta half as compliant. Explain why the pulse pressure of the elderly is wide, and what it costs the heart.

Solution

Solution of Exercise 16.10.

RC=2sRC = 2\,\mathrm{s}: 120e0.4=80mmHg120e^{-0.4} = 80\,\mathrm{mmHg}. C=1C = 1: RC=1RC = 1, 120e0.8=54mmHg120e^{-0.8} = 54\,\mathrm{mmHg} — and the same stroke volume raises the systolic pressure more in a stiff aorta. A wide pulse pressure means a higher peak against which the heart must eject, more work and more oxygen for the same output.

Exercise 16.11 ★★★

The systemic resistance is R=(PartPven)/QR = (P_{\text{art}} - P_{\text{ven}})/Q. Compute it at rest (95595 - 5 mmHg, 5L/min5\,\mathrm{L}/\mathrm{min}) and in exercise (1105110 - 5, 25L/min25\,\mathrm{L}/\mathrm{min}). By what factor must the mean arteriolar radius have changed, if the arterioles carry the whole resistance?

Solution

Solution of Exercise 16.11.

Rest: 90/83=1.08mmHgs/mL90/83 = 1.08\,\mathrm{mmHg}\,\mathrm{s}/\mathrm{mL}; exercise: 105/417=0.25mmHgs/mL105/417 = 0.25\,\mathrm{mmHg}\,\mathrm{s}/\mathrm{mL}, a fourfold fall. Since Rr4R \propto r^{-4}, rr has risen by 41/4=1.414^{1/4} = 1.41: the arterioles have widened by 41%41\,\% on average.

Exercise 16.12 ★★★

“The circulation is built so that the blood is slow where it must exchange and fast everywhere else.” Discuss, with the continuity equation, Poiseuille’s law and the geometry of the tree, and say why an open circulation cannot do the same.

Solution

Solution of Exercise 16.12.

Continuity fixes the velocity at each level by the total cross-section, and the tree is built so that the section is a thousand times the aorta’s in the capillaries and small again in the veins; Poiseuille’s law puts the resistance in the arterioles, where muscle can change it, and leaves the wide vessels nearly free of loss. An open circulation has no capillaries to slow the blood at a defined place, no vessels in which to set a resistance, and no way to direct flow to one organ — it can only stir.

16.6 Problem: The Circulation in Numbers

Problem 16.1

Weekend problem — Harvey’s sum redone, the vessel tree’s pressures and speeds computed by Poiseuille and continuity, the capillaries’ daily filtration balanced, and the aorta’s smoothing modelled, ending on the cardiac output, the arteriolar pressure drop, the day’s filtrate and the diastolic pressure

Data: stroke volume 70mL70\,\mathrm{mL}, heart rate 72min172\,\mathrm{min}^{-1}, blood volume 5L5\,\mathrm{L}, η=3×103Pas\eta = 3 \times 10^{-3}\,\mathrm{Pa}\,\mathrm{s}, 1mmHg=133Pa1\,\mathrm{mmHg} = 133\,\mathrm{Pa}. Aorta: radius 1.25cm1.25\,\mathrm{cm}, length 40cm40\,\mathrm{cm}. Arterioles: 3×1063\times 10^{6} in parallel, each of radius 15µm15\,\text{µ}\mathrm{m} and length 1mm1\,\mathrm{mm}. Capillaries: 4×10104\times 10^{10}, radius 3µm3\,\text{µ}\mathrm{m}, length 1mm1\,\mathrm{mm}, a quarter of them open at rest. Starling: PcP_c from 35 to 15mmHg15\,\mathrm{mmHg} along a capillary, πc=25mmHg\pi_c = 25\,\mathrm{mmHg}. Windkessel: C=2mL/mmHgC = 2\,\mathrm{mL}/\mathrm{mmHg}, diastole 0.8s0.8\,\mathrm{s}.

Part I — Harvey’s sum.

  1. Compute the cardiac output in litres per minute and per day.
  2. How many times does the blood volume circulate in a day?
  3. Harvey’s estimate was 2 ounces (57g57\,\mathrm{g}) per beat, of which he supposed at least a quarter expelled, at 72 beats a minute. What mass of blood did that give per hour, and how did it compare with a man’s weight?
  4. Why was this an argument for circulation rather than for continuous production and consumption?
  5. Describe the ligature experiment and what the valves showed.
  6. What could Harvey not see, and who saw it?

Part II — The tree.

  1. Compute the mean velocity in the aorta.
  2. Compute the pressure drop along the aorta by Poiseuille’s law, in mmHg.
  3. Compute the resistance of one arteriole and of the 3×1063\times 10^{6} in parallel.
  4. Compute the pressure drop across the arterioles at the resting output, in mmHg.
  5. Compute the total cross-section of the open capillaries and the mean velocity in them; then the transit time through one.
  6. The arterioles constrict so that their radius falls by 10%10\,\%. Recompute the drop. What must the heart do to keep the same output?

Part III — The capillaries.

  1. Compute the net filtration pressure at the arterial end, at the venous end, and at the midpoint (take PcP_c to fall linearly).
  2. Split the capillary into the filtering half and the reabsorbing half and estimate the fluid filtered and reabsorbed per day over the whole body, taking the net pressures averaged over each half as +10+10 and 8.5mmHg-8.5\,\mathrm{mmHg} and each half moving 2L2\,\mathrm{L} a day per mmHg.
  3. Deduce the lymph flow.
  4. Plasma albumin falls to 20g/L20\,\mathrm{g}/\mathrm{L}. Recompute πc\pi_c (assume it scales with albumin) and the net pressures at the two ends. What happens?
  5. Venous pressure rises so that PcP_c runs from 35 to 28mmHg28\,\mathrm{mmHg}. Recompute the average net pressure and the daily balance. Where does the fluid go?
  6. Compute the total capillary surface (cylinders, all of them) and the time a molecule takes to diffuse to a cell 20µm20\,\text{µ}\mathrm{m} from a capillary (D=1×109m2/sD = 1 \times 10^{-9}\,\mathrm{m}^{2}/\mathrm{s}).

Part IV — The aorta as a reservoir.

  1. Compute the systemic resistance from a mean pressure of 93mmHg93\,\mathrm{mmHg}, venous 3mmHg3\,\mathrm{mmHg} and the resting output, in mmHgs/mL\mathrm{mmHg}\,\mathrm{s}/\mathrm{mL}.
  2. Compute the time constant RCRC and the diastolic pressure after 0.8s0.8\,\mathrm{s} from a systolic of 120mmHg120\,\mathrm{mmHg}.
  3. Recompute for C=1mL/mmHgC = 1\,\mathrm{mL}/\mathrm{mmHg}. What has happened to the pulse pressure?
  4. The heart rate rises to 120120 and diastole shortens to 0.3s0.3\,\mathrm{s}. Compute the diastolic pressure.
  5. Of the 70mL70\,\mathrm{mL} ejected, how much is stored in the arteries during systole if the pressure rises by 20mmHg20\,\mathrm{mmHg}? Where does the rest go?
  6. Explain why the coronary arteries, which fill in diastole, depend on the aorta’s recoil.
  7. State the result: the cardiac output, the arteriolar pressure drop, the day’s net filtrate, and the diastolic pressure for C=2C = 2 and C=1C = 1.
Solution

Solution of Problem 16.1.

1. 70×72=5.0L/min70\times 72 = 5.0\,\mathrm{L}/\mathrm{min}; 7300L7300\,\mathrm{L} a day. 2. 7300/514507300/5 \approx 1450 times. 3. A quarter of 57g57\,\mathrm{g} at 72 beats a minute: 14g14\,\mathrm{g} ×4320=62kg\times 4320 = 62\,\mathrm{kg} an hour — about the weight of a man. 4. No food could supply, and no tissue consume, a man’s weight of blood every hour; the only escape is that the same blood returns to the heart. 5. A cord tied round the arm swells the veins below it, not above, so blood in the veins moves toward the heart; pressing the blood in a vein toward the hand, it stops at the valves and cannot be pushed back — the valves permit flow toward the heart only. 6. The capillaries joining arteries to veins; Malpighi saw them in the frog’s lung in 1661. 7. Area π×1.252=4.9cm2\pi\times 1.25^{2} = 4.9\,\mathrm{cm}^{2}; 83/4.9=17cm/s83/4.9 = 17\,\mathrm{cm}/\mathrm{s}. 8. 8×3×103×0.4×8.3×105/(π×2.44×108)=10Pa8\times 3\times 10^{-3}\times 0.4\times 8.3\times 10^{-5}/(\pi\times 2.44\times 10^{-8}) = 10\,\mathrm{Pa}, 0.08mmHg0.08\,\mathrm{mmHg}. 9. R1=8×3×103×103/(π×5.06×1020)=1.5×1014Pas/m3R_{1} = 8\times 3\times 10^{-3}\times 10^{-3}/(\pi\times 5.06\times 10^{-20}) = 1.5 \times 10^{14}\,\mathrm{Pa}\,\mathrm{s}/\mathrm{m}^{3}; in parallel, 1.5×1014/3×106=5.0×107Pas/m31.5\times 10^{14}/3\times 10^{6} = 5.0 \times 10^{7}\,\mathrm{Pa}\,\mathrm{s}/\mathrm{m}^{3}. 10. 8.3×105×5.0×107=4200Pa=31mmHg8.3\times 10^{-5}\times 5.0\times 10^{7} = 4200\,\mathrm{Pa} = 31\,\mathrm{mmHg}. 11. Open capillaries 101010^{10}, each π(3×106)2=2.8×1011m2\pi(3\times 10^{-6})^{2} = 2.8 \times 10^{-11}\,\mathrm{m}^{2}: 0.28m20.28\,\mathrm{m}^{2} =2800cm2= 2800\,\mathrm{cm}^{2}; v=83/2800=0.03cm/sv = 83/2800 = 0.03\,\mathrm{cm}/\mathrm{s}; transit 0.1/0.03=3.3s0.1/0.03 = 3.3\,\mathrm{s}. 12. Resistance ×(1/0.9)4=1.52\times(1/0.9)^{4} = 1.52: 47mmHg47\,\mathrm{mmHg}; the heart must raise the arterial pressure by 16mmHg16\,\mathrm{mmHg} or the output falls by a third. 13. +10+10, 10-10 and 00 mmHg. 14. Filtration 10×2=20L10\times 2 = 20\,\mathrm{L} a day; reabsorption 8.5×2=17L8.5\times 2 = 17\,\mathrm{L}. 15. 3L3\,\mathrm{L} a day of lymph. 16. πc=12.5mmHg\pi_c = 12.5\,\mathrm{mmHg}: net +22.5+22.5 at the arterial end and +2.5+2.5 at the venous end — filtration everywhere, no reabsorption: oedema. 17. Net +10+10 and +3+3, average +6.5+6.5: filtration along the whole capillary, some 26L26\,\mathrm{L} a day; the lymphatics cannot carry it and the fluid accumulates in the tissues, feet first. 18. 4×1010×2π×3×106×103=750m24\times 10^{10}\times 2\pi\times 3\times 10^{-6}\times 10^{-3} = 750\,\mathrm{m}^{2}; t=x2/2D=(2×105)2/(2×109)=0.2st = x^{2}/2D = (2\times 10^{-5})^{2}/ (2\times 10^{-9}) = 0.2\,\mathrm{s}. 19. (933)/83=1.08mmHgs/mL(93 - 3)/83 = 1.08\,\mathrm{mmHg}\,\mathrm{s}/\mathrm{mL}. 20. RC=2.2sRC = 2.2\,\mathrm{s}; 120e0.8/2.2=120×0.69=83mmHg120e^{-0.8/2.2} = 120\times 0.69 = 83\,\mathrm{mmHg}. 21. RC=1.1sRC = 1.1\,\mathrm{s}; 120e0.73=58mmHg120e^{-0.73} = 58\,\mathrm{mmHg}: the pulse pressure widens from 37 to 62mmHg62\,\mathrm{mmHg}. 22. 120e0.3/2.2=105mmHg120e^{-0.3/2.2} = 105\,\mathrm{mmHg}: at a fast rate the pressure barely falls between beats. 23. CΔP=2×20=40mLC\Delta P = 2\times 20 = 40\,\mathrm{mL} stored; the other 30mL30\,\mathrm{mL} run off through the arterioles during systole itself. 24. The contracting ventricle squeezes its own vessels shut in systole, so the heart muscle is perfused in diastole, by the pressure that the recoiling aorta maintains; a stiff aorta that lets the diastolic pressure collapse starves the heart between beats. 25. Output 5L/min5\,\mathrm{L}/\mathrm{min}; arteriolar drop 31mmHg31\,\mathrm{mmHg}; net filtrate 3L3\,\mathrm{L} a day to the lymph; diastolic 83mmHg83\,\mathrm{mmHg} for C=2C = 2 and 58mmHg58\,\mathrm{mmHg} for C=1C = 1.

Terms defined in this chapter

See all 479 terms in the glossary