Chemistry · Book 1 · Grades 1–12

School Chemistry — Grades 1 to 12

School Chemistry — Grades 1 to 12 · Grades 1–12

17Ions and Ionic Solutions

Two clear drinks stand on a gym bench: a bottle of sports drink, sold for its “electrolytes”, and a glass of sugared water. In a laboratory, two metal plates connected to a battery and a small bulb are dipped into each in turn. In the sports drink the bulb lights up; in the sugared water it stays dark. Something in the first liquid carries electric charge, and the sugar does not. That something is ions.

You already know

An atom has a nucleus with ZZ protons, each of charge +e+e, and ZZ electrons around it, each of charge −e-e: the atom is neutral (Chapter 16). A solute dissolved in water gives an aqueous solution (Chapter 9). A characteristic test detects a species by a visible result (Chapter 10).

A sports drink and a glass of water: the drink contains dissolved ions.
A sports drink and a glass of water: the drink contains dissolved ions.

17.1 Atoms that gain or lose electrons

Definition 17.1 (Ion, cation, anion)

An ion is an atom, or a group of atoms, that has lost or gained one or more electrons, and so carries an electric charge. An ion with a positive charge, having lost electrons, is a cation; an ion with a negative charge, having gained electrons, is an anion. The charge is written at the top right of the formula: NaX+\ce{Na+}, CuX2+\ce{Cu^{2+}}, ClX−\ce{Cl-}.

Example 17.2 (Sodium and chlorine)

A sodium atom, 11 protons and 11 electrons, loses one electron: it becomes the sodium ion NaX+\ce{Na+}, 11 protons and 10 electrons, charge +1+1:

Na→NaX++eX−.\ce{Na -> Na+ + e-}.

A chlorine atom, 17 protons and 17 electrons, gains one electron: it becomes the chloride ion ClX−\ce{Cl-}, 17 protons and 18 electrons:

Cl+eX−→ClX−.\ce{Cl + e- -> Cl-}.
A sodium atom becomes a sodium ion by losing an electron; a chlorine atom becomes a chloride ion by gaining one. The protons do not change.
A sodium atom becomes a sodium ion by losing an electron; a chlorine atom becomes a chloride ion by gaining one. The protons do not change.

Proposition 17.3 (Some common ions)

Monatomic ions are made from one atom; polyatomic ions from a group of atoms that stays together:

cationsanions
sodiumNaX+\ce{Na+}chlorideClX−\ce{Cl-}
potassiumKX+\ce{K+}hydroxideOHX−\ce{OH-}
calciumCaX2+\ce{Ca^{2+}}nitrateNOX3X−\ce{NO3-}
magnesiumMgX2+\ce{Mg^{2+}}carbonateCOX3X2−\ce{CO3^{2-}}
copper(II)CuX2+\ce{Cu^{2+}}sulfateSOX4X2−\ce{SO4^{2-}}
iron(II), iron(III)FeX2+\ce{Fe^{2+}}, FeX3+\ce{Fe^{3+}}
zincZnX2+\ce{Zn^{2+}}
aluminiumAlX3+\ce{Al^{3+}}
ammoniumNHX4X+\ce{NH4+}

17.2 Ionic compounds and their formulas

Definition 17.4 (Ionic compound)

An ionic compound is made of cations and anions in such numbers that the whole carries no charge. Its formula gives the proportion of the ions, without their charges: NaCl\ce{NaCl} for sodium chloride, one NaX+\ce{Na+} for each ClX−\ce{Cl-}; CaClX2\ce{CaCl2} for calcium chloride, two ClX−\ce{Cl-} for each CaX2+\ce{Ca^{2+}}.

Method 17.5 (Writing the formula of an ionic compound)

  1. Write the two ions with their charges, cation first.
  2. Find the smallest numbers of each that make the total charge zero.
  3. Write these numbers as subscripts; a polyatomic ion needing a subscript goes in brackets.

Aluminium oxide: AlX3+\ce{Al^{3+}} and OX2−\ce{O^{2-}}; 2×(+3)+3×(−2)=02 \times (+3) + 3 \times (-2) = 0, so AlX2OX3\ce{Al2O3}. Iron(III) hydroxide: FeX3+\ce{Fe^{3+}} and three OHX−\ce{OH-}: Fe(OH)X3\ce{Fe(OH)3}.

Proposition 17.6 (An ionic solid is a stack of ions)

In a crystal of salt, sodium ions and chloride ions alternate in a regular three-dimensional stack, each ion surrounded by ions of the opposite charge, which hold it in place. A grain of table salt holds billions of billions of them; its cubic shape reflects the cubic stack.

One layer of a salt crystal: sodium ions (purple, smaller) and chloride ions (green) alternate.
Halite, natural rock salt. Photo: Robert M. Lavinsky, CC BY-SA 3.0.

17.3 Ionic solutions conduct

Notation 17.7 (The state symbol (aq))

An ion or a molecule dissolved in water is marked (aq), for aqueous: NaX+(aq)\ce{Na+(aq)}, ClX−(aq)\ce{Cl-(aq)}.

Proposition 17.8 (Ionic solutions conduct electricity)

When an ionic compound dissolves in water, its ions separate and move freely in the solution: salt water contains NaX+(aq)\ce{Na+(aq)} and ClX−(aq)\ce{Cl-(aq)}. Moving ions carry electric charge, so an ionic solution conducts electricity. A solution of sugar, whose molecules carry no charge, does not; nor does very pure water.

In the lab — Which liquids conduct?

Two metal plates, a low-voltage battery and a small bulb are joined in a circuit by the teacher; the plates are dipped in turn into distilled water, sugar water, salt water and a copper sulfate solution, and rinsed between each. The bulb lights only with the two ionic solutions.

The conductivity test: with salt water, ions carry the current and the bulb lights; sugar water contains no ions and the bulb stays dark.
The conductivity test: with salt water, ions carry the current and the bulb lights; sugar water contains no ions and the bulb stays dark.

17.4 Precipitation tests for ions

Definition 17.9 (Precipitate)

When two solutions are mixed, a cation of one and an anion of the other may form an ionic compound that does not dissolve. It appears as a fine solid that clouds the liquid and settles: a precipitate. The reaction is a precipitation.

Proposition 17.10 (Tests for common ions)

A few drops of a reagent solution identify an ion by the colour of the precipitate it forms:

ion looked forreagentprecipitatecolour
copper(II) CuX2+\ce{Cu^{2+}}sodium hydroxideCu(OH)X2\ce{Cu(OH)2}blue
iron(II) FeX2+\ce{Fe^{2+}}sodium hydroxideFe(OH)X2\ce{Fe(OH)2}green
iron(III) FeX3+\ce{Fe^{3+}}sodium hydroxideFe(OH)X3\ce{Fe(OH)3}orange-brown
zinc ZnX2+\ce{Zn^{2+}}sodium hydroxideZn(OH)X2\ce{Zn(OH)2}white
aluminium AlX3+\ce{Al^{3+}}sodium hydroxideAl(OH)X3\ce{Al(OH)3}white
chloride ClX−\ce{Cl-}silver nitrateAgCl\ce{AgCl}white, darkens in light

Example 17.11 (Writing a precipitation)

Only the ions that form the solid are written; the others stay dissolved and take no part:

CuX2+(aq)+2 OHX−(aq)→Cu(OH)X2(s),AgX+(aq)+ClX−(aq)→AgCl(s).\ce{Cu^{2+}(aq) + 2OH-(aq) -> Cu(OH)2(s)}, \qquad \ce{Ag+(aq) + Cl-(aq) -> AgCl(s)}.
Precipitates formed with sodium hydroxide (first five tubes) and with silver nitrate (last tube).
Precipitates formed with sodium hydroxide (first five tubes) and with silver nitrate (last tube).

Safety

Sodium hydroxide: causes severe skin burns and eye damage, and may be corrosive to metals (GHS05); irritating to skin and eyes in dilute form (GHS07). Silver nitrate, the chloride reagent, is an oxidiser, corrosive and very toxic to aquatic life. Goggles, gloves; reagents dispensed by drops by the teacher.

Method 17.12 (Testing for an ion)

  1. Pour a little of the solution to be tested into a test tube.
  2. Add the reagent drop by drop.
  3. Note the colour of any precipitate and compare with the table.
  4. Conclude, and remember that a test identifies an ion, not a compound: the iron(III) chloride solution gives both the FeX3+\ce{Fe^{3+}} test and the ClX−\ce{Cl-} test.

17.5 Exercises

Exercise 17.3 ★

Write the formulas of potassium chloride, magnesium chloride and calcium oxide (oxide ion: OX2−\ce{O^{2-}}).

Solution

Solution of Exercise 17.3.

KCl\ce{KCl}, MgClX2\ce{MgCl2}, CaO\ce{CaO}.

Exercise 17.4 ★

Why does salt water conduct electricity while sugar water does not?

Solution

Solution of Exercise 17.4.

Salt water contains ions, NaX+(aq)\ce{Na+(aq)} and ClX−(aq)\ce{Cl-(aq)}, which move and carry charge. Sugar molecules carry no charge.

Exercise 17.5 ★★

Write the formulas of copper(II) sulfate, aluminium chloride and sodium carbonate.

Solution

Solution of Exercise 17.5.

CuSOX4\ce{CuSO4}, AlClX3\ce{AlCl3}, NaX2COX3\ce{Na2CO3}.

Exercise 17.6 ★★

Sodium hydroxide added to a solution gives an orange-brown precipitate. Which ion does the solution contain? Write the equation of the precipitation.

Solution

Solution of Exercise 17.6.

Iron(III), FeX3+\ce{Fe^{3+}}: FeX3+(aq)+3 OHX−(aq)→Fe(OH)X3(s)\ce{Fe^{3+}(aq) + 3OH-(aq) -> Fe(OH)3(s)}.

Exercise 17.7 ★★

How many electrons does the sulfate ion SOX4X2−\ce{SO4^{2-}} carry in excess of its protons? The nitrate ion NOX3X−\ce{NO3-}?

Solution

Solution of Exercise 17.7.

Sulfate: 2 extra electrons. Nitrate: 1.

Exercise 17.8 ★★

A solution gives a white precipitate with silver nitrate and a blue one with sodium hydroxide. Name the dissolved ionic compound and write its formula.

Solution

Solution of Exercise 17.8.

White with silver nitrate: ClX−\ce{Cl-}. Blue with sodium hydroxide: CuX2+\ce{Cu^{2+}}. Copper(II) chloride, CuClX2\ce{CuCl2}.

Exercise 17.9 ★★

Look at the figure of the salt crystal layer. How many neighbours of opposite charge does an ion in the middle of the layer have in this layer?

Solution

Solution of Exercise 17.9.

Four: one on each side (left, right, above, below).

Exercise 17.10 ★★

Write the equation of the precipitation of iron(II) hydroxide from FeX2+\ce{Fe^{2+}} and OHX−\ce{OH-} ions.

Solution

Solution of Exercise 17.10.

FeX2+(aq)+2 OHX−(aq)→Fe(OH)X2(s)\ce{Fe^{2+}(aq) + 2OH-(aq) -> Fe(OH)2(s)}.

Exercise 17.11 ★★★

A white powder may be zinc chloride or sodium chloride. Dissolved in water, it gives a white precipitate with sodium hydroxide. Which is it? Write the equation.

Solution

Solution of Exercise 17.11.

Zinc chloride: sodium ions give no precipitate with sodium hydroxide, zinc ions give a white one: ZnX2+(aq)+2 OHX−(aq)→Zn(OH)X2(s)\ce{Zn^{2+}(aq) + 2OH-(aq) -> Zn(OH)2(s)}.

Exercise 17.12 ★★★

In a crystal of calcium chloride, how many chloride ions are there for 1000 calcium ions? Check that the crystal is neutral.

Solution

Solution of Exercise 17.12.

CaClX2\ce{CaCl2}: 2000 chloride ions. Charges: 1000×(+2)+2000×(−1)=01000 \times (+2) + 2000 \times (-1) = 0.

17.6 Problem: The Rusty Well

Problem 17.1

Weekend problem — orange stains in a farmhouse sink, two tests, and the number of iron ions in a litre of well water

The water of a farmhouse well leaves orange stains in the sink. A laboratory receives a sample. Freshly drawn, the water is clear; with sodium hydroxide it gives a green precipitate, which turns orange-brown within an hour at the surface, where it meets the air. The laboratory measures 0.30 mg0.30\,\mathrm{mg} of iron, in the form of iron ions, per litre. Take the mass of a nucleon as 1.67×10−27 kg1.67 \times 10^{-27}\,\mathrm{kg}, and 56 nucleons for an iron atom.

Part I — The tests.

  1. Which ion does the green precipitate show? Give the formula of the precipitate.
  2. Which ion does the orange-brown precipitate show? Give its formula.
  3. An iron(II) ion and an iron(III) ion differ by one electron. Which has more electrons? How many electrons does each have (iron: Z=26Z = 26)?
  4. Write the equation of the precipitation of iron(III) hydroxide.

Part II — The stains.

  1. In the sink, the clear water slowly turns cloudy and orange. Which ion does the water hold when it comes out of the well, and which does it end up holding?
  2. Write the formula of the ionic compound formed by iron(III) ions and hydroxide ions, and check that it is neutral.
  3. Can the iron of the water be removed by filtering the water as it comes out of the well? After it has turned orange? Explain.
  4. Is a water containing iron ions a pure substance? A homogeneous mixture?

Part III — Counting the ions.

  1. Compute the mass of an iron atom, in kilograms.
  2. Convert 0.30 mg0.30\,\mathrm{mg} into kilograms.
  3. Why may the mass of an iron ion be taken equal to that of an iron atom?
  4. Compute the number of iron ions in a litre of the well water.
Solution

Solution of Problem 17.1.

1. Iron(II), FeX2+\ce{Fe^{2+}}: Fe(OH)X2\ce{Fe(OH)2}.

2. Iron(III), FeX3+\ce{Fe^{3+}}: Fe(OH)X3\ce{Fe(OH)3}.

3. FeX2+\ce{Fe^{2+}} has one more: 26−2=2426 - 2 = 24 electrons, against 26−3=2326 - 3 = 23 for FeX3+\ce{Fe^{3+}}.

4. FeX3+(aq)+3 OHX−(aq)→Fe(OH)X3(s)\ce{Fe^{3+}(aq) + 3OH-(aq) -> Fe(OH)3(s)}.

5. It comes out holding iron(II) ions; in contact with the air they become iron(III) ions, which form the orange solid.

6. Fe(OH)X3\ce{Fe(OH)3}: (+3)+3×(−1)=0(+3) + 3 \times (-1) = 0.

7. Not as it comes out: the iron ions are dissolved and pass through a filter. Once the orange solid has formed, yes: it is a precipitate, held back by a filter.

8. No: a mixture (water and dissolved ions). Freshly drawn and clear, it is homogeneous.

9. 56×1.67×10−27=9.35×10−26 kg56 \times 1.67 \times 10^{-27} = 9.35 \times 10^{-26}\,\mathrm{kg}.

10. 0.30 mg=0.30×10−6 kg=3.0×10−7 kg0.30\,\mathrm{mg} = 0.30 \times 10^{-6}\,\mathrm{kg} = 3.0 \times 10^{-7}\,\mathrm{kg}.

11. An ion differs from the atom by two or three electrons, whose mass is negligible beside the nucleus.

12. 3.0×10−7/9.35×10−26≈3.2×10183.0 \times 10^{-7} / 9.35 \times 10^{-26} \approx 3.2 \times 10^{18} iron ions per litre.

Terms defined in this chapter

See all 852 terms in the glossary