Chemistry · Book 1 · Grades 1–12

School Chemistry — Grades 1 to 12

School Chemistry — Grades 1 to 12 · Grades 1–12

37The Energy of Reactions: Combustion and Bond Energies

Break the seal of a hand warmer and, a minute later, it is too hot to hold for long; squeeze a cold pack and it chills a sprained ankle; a city bus runs all day on hydrogen and leaves only water vapour behind it. Chemical transformations do not only turn substances into others: they release energy, or take it in. Where does that energy come from, and how much of it can a fuel give?

You already know

In a complete combustion, a fuel made of carbon and hydrogen burns in dioxygen to give carbon dioxide and water (Chapter 14). A covalent bond is a shared pair of electrons; Lewis structures show every bond of a molecule (Chapter 24). The amount of substance is counted in moles (Chapter 25).

A hand warmer: a reaction inside the pouch releases heat.
A hand warmer: a reaction inside the pouch releases heat.

37.1 Exothermic and endothermic transformations

Definition 37.1 (Exothermic, endothermic)

A transformation is exothermic if it releases energy to its surroundings, usually as heat: the surroundings warm up. It is endothermic if it takes in energy from its surroundings: they cool down, or the transformation needs heating to go on.

Example 37.2 (Warm and cold)

Combustions are exothermic, and so is the slow reaction of iron powder with the dioxygen of the air inside a hand warmer. The dissolving of ammonium nitrate in water, used in cold packs, is endothermic; so is the decomposition of limestone into quicklime and carbon dioxide, which takes place only in a very hot kiln.

Energy diagrams. In an exothermic reaction the products hold less energy than the reactants, and the difference is released; in an endothermic one they hold more, and it must be supplied.
Energy diagrams. In an exothermic reaction the products hold less energy than the reactants, and the difference is released; in an endothermic one they hold more, and it must be supplied.

37.2 The energy released by a combustion

Definition 37.3 (Molar energy of combustion)

The molar energy of combustion EcE_c of a fuel is the energy released by the complete combustion of one mole of it, in kJ/mol\mathrm{kJ}/\mathrm{mol}, the water formed being liquid.

Proposition 37.4 (Energy released by nn moles)

The complete combustion of an amount nn of fuel releases the energy Q=n×EcQ = n \times E_c. For methane, Ec=890.7 kJ/molE_c = 890.7\,\mathrm{kJ}/\mathrm{mol}: burning 1.00 mol1.00\,\mathrm{mol} (16.0 g16.0\,\mathrm{g}) of it releases about 891 kJ891\,\mathrm{kJ}.

Proof. Each mole of fuel burnt releases EcE_c; nn moles release nn times more. ∎

In the lab — Heating water with a spirit burner

A spirit burner of ethanol is weighed, then lit under a metal can holding 200 g200\,\mathrm{g} of water, with a thermometer in it. When the water has warmed by 25 ∘C25\,{}^{\circ}\mathrm{C}, the flame is put out and the burner weighed again: it has lost 1.50 g1.50\,\mathrm{g} of ethanol. The energy taken by the water is computed with the physics formula Q=m c ΔθQ = m\, c\, \Delta\theta, where c=4.18 J/(g ∘C)c = 4.18\,\mathrm{J}/(\mathrm{g}\,{}^{\circ}\mathrm{C}) is the specific heat of water. It is far below the energy the ethanol could release: much of the heat warms the air, the can and the burner, and some of the ethanol burns incompletely.

Measuring the energy given by a fuel: a spirit burner heats a can of water whose temperature rise is measured.
Measuring the energy given by a fuel: a spirit burner heats a can of water whose temperature rise is measured.

Example 37.5 (The spirit burner in numbers)

The water received Q=200×4.18×25=2.09×104 JQ = 200 \times 4.18 \times 25 = 2.09 \times 10^{4}\,\mathrm{J}, that is 20.9 kJ20.9\,\mathrm{kJ}. The ethanol burnt, 1.50 g1.50\,\mathrm{g}, is 1.50/46.0=0.0326 mol1.50 / 46.0 = 0.0326\,\mathrm{mol}; with Ec=1367.6 kJ/molE_c = 1367.6\,\mathrm{kJ}/\mathrm{mol} it could release 0.0326×1367.6=44.6 kJ0.0326 \times 1367.6 = 44.6\,\mathrm{kJ}. Only 20.9/44.6≈47 %20.9 / 44.6 \approx 47\,\% of it reached the water.

37.3 Bond energies

Definition 37.6 (Bond energy)

The bond energy of a covalent bond is the energy needed to break one mole of such bonds, the molecules and atoms being gases. Tables give average values, measured over many molecules, in kJ/mol\mathrm{kJ}/\mathrm{mol}.

bondkJ/mol\mathrm{kJ}/\mathrm{mol}bondkJ/mol\mathrm{kJ}/\mathrm{mol}bondkJ/mol\mathrm{kJ}/\mathrm{mol}
H−H\ce{H-H}436C−C\ce{C-C}345O=O\ce{O=O}498
C−H\ce{C-H}415C=C\ce{C=C}611N≡N\ce{N#N}946
N−H\ce{N-H}390C−O\ce{C-O}350Cl−Cl\ce{Cl-Cl}243
O−H\ce{O-H}464C=O\ce{C=O}741H−Cl\ce{H-Cl}432
Average bond energies. Breaking a bond always costs energy; forming it gives the same energy back.
The combustion of methane as two imaginary steps, with average bond energies: breaking every bond, then forming the new ones. The estimate, -682\, kJ per mole of methane, is exothermic.
The combustion of methane as two imaginary steps, with average bond energies: breaking every bond, then forming the new ones. The estimate, −682 kJ-682\,\mathrm{kJ} per mole of methane, is exothermic.

Proposition 37.7 (Estimating a reaction energy)

For a reaction between gases, the energy taken in, ErE_r (negative if energy is released), is approximately

Er≈∑E(bonds broken)−∑E(bonds formed).E_r \approx \sum E(\text{bonds broken}) - \sum E(\text{bonds formed}) .

If Er<0E_r < 0, more energy is released by forming the new bonds than is needed to break the old ones: the reaction is exothermic.

Proof. Imagine the reaction in two steps: every bond of the reactants is broken, which costs the first sum and leaves separate atoms; then the bonds of the products form, which gives back the second sum. The result is only an estimate, because tables give averages over many molecules. ∎

Method 37.8 (Estimating a reaction energy from bond energies)

  1. Write the balanced equation and the Lewis structure of every molecule.
  2. Count the bonds of each kind broken in the reactants and formed in the products, with the coefficients.
  3. Add up the energies of the bonds broken, subtract those of the bonds formed.
  4. Conclude: a negative result means an exothermic reaction.

Example 37.9 (Hydrogen and chlorine)

For HX2+ClX2→2 HCl\ce{H2 + Cl2 -> 2HCl}: one H−H\ce{H-H} and one Cl−Cl\ce{Cl-Cl} broken, 436+243=679 kJ436 + 243 = 679\,\mathrm{kJ}; two H−Cl\ce{H-Cl} formed, 2×432=864 kJ2 \times 432 = 864\,\mathrm{kJ}. So Er≈679−864=−185 kJE_r \approx 679 - 864 = -185\,\mathrm{kJ} per mole of reaction: exothermic.

Remark 37.10 (Estimate and measurement)

The measured energy released by burning one mole of methane is 890.7 kJ890.7\,\mathrm{kJ}, larger than the estimate. Three reasons: the C=O\ce{C=O} bonds of carbon dioxide are stronger than the average C=O\ce{C=O} of the table; the measured value is for liquid water, and condensing the water vapour releases more energy; and average bond energies are only averages. The bond-energy method gives the sign and the order of magnitude, not the exact value.

37.4 Comparing fuels

Energy released by the complete combustion of one kilogram of five fuels (water formed liquid). Hydrogen gives by far the most per kilogram; ethanol, already partly “burnt” (it contains oxygen), the least.
Energy released by the complete combustion of one kilogram of five fuels (water formed liquid). Hydrogen gives by far the most per kilogram; ethanol, already partly “burnt” (it contains oxygen), the least.

Example 37.11 (Carbon dioxide per megajoule)

Burning one mole of methane releases 890.7 kJ890.7\,\mathrm{kJ} and one mole of carbon dioxide, 44.0 g44.0\,\mathrm{g}. For one megajoule, 1000 kJ1000\,\mathrm{kJ}, it releases 44.0×1000/890.7=49.4 g44.0 \times 1000 / 890.7 = 49.4\,\mathrm{g} of carbon dioxide. Ethanol, with two moles of carbon dioxide per 1367.6 kJ1367.6\,\mathrm{kJ}, releases 88.0×1000/1367.6=64.3 g88.0 \times 1000 / 1367.6 = 64.3\,\mathrm{g} per megajoule. Hydrogen releases none: its only product is water.

A bus at a hydrogen station: its fuel releases only water.
A bus at a hydrogen station: its fuel releases only water.

Safety

Ethanol is highly flammable and irritating to the eyes. A spirit burner is filled away from any flame, never refilled while hot, and used by the teacher on a heat-proof mat.

37.5 Exercises

Exercise 37.2 ★

What energy does the complete combustion of 3.0 mol3.0\,\mathrm{mol} of methane release?

Solution

Solution of Exercise 37.2.

Q=3.0×890.7=2.7×103 kJQ = 3.0 \times 890.7 = 2.7 \times 10^{3}\,\mathrm{kJ}, about 2.7 MJ2.7\,\mathrm{MJ}.

Exercise 37.3 ★

On the energy diagram of an exothermic reaction, which holds more energy, the reactants or the products? Where does the difference go?

Solution

Solution of Exercise 37.3.

The reactants. The difference is released to the surroundings, mostly as heat.

Exercise 37.4 ★

What energy does the complete combustion of 100 g100\,\mathrm{g} of ethanol release?

Solution

Solution of Exercise 37.4.

n=100/46.0=2.17 moln = 100 / 46.0 = 2.17\,\mathrm{mol}; Q=2.17×1367.6=2.97×103 kJQ = 2.17 \times 1367.6 = 2.97 \times 10^{3}\,\mathrm{kJ}, about 3.0 MJ3.0\,\mathrm{MJ}.

Exercise 37.5 ★

What is a bond energy? Why does breaking a bond always cost energy?

Solution

Solution of Exercise 37.5.

The energy needed to break one mole of these bonds, molecules and atoms being gases. The shared pair holds the two atoms together: pulling them apart works against that attraction, which takes energy.

Exercise 37.6 ★★

Estimate, with bond energies, the energy of the reaction 2 HX2+OX2→2 HX2O\ce{2H2 + O2 -> 2H2O}, all gases. Is it exothermic?

Solution

Solution of Exercise 37.6.

Broken: 2×436+498=1370 kJ2 \times 436 + 498 = 1370\,\mathrm{kJ}; formed: 4×464=1856 kJ4 \times 464 = 1856\,\mathrm{kJ}; Er≈1370−1856=−486 kJE_r \approx 1370 - 1856 = -486\,\mathrm{kJ}: exothermic.

Exercise 37.7 ★★

Estimate the energy of the combustion of ethanol, CX2HX5OH+3 OX2→2 COX2+3 HX2O\ce{C2H5OH + 3O2 -> 2CO2 + 3H2O}, with bond energies (draw the Lewis structure of ethanol first), and compare with the measured 1367.6 kJ/mol1367.6\,\mathrm{kJ}/\mathrm{mol}.

Solution

Solution of Exercise 37.7.

Ethanol CHX3−CHX2−O−H\ce{CH3-CH2-O-H} has 5 C−H\ce{C-H}, 1 C−C\ce{C-C}, 1 C−O\ce{C-O} and 1 O−H\ce{O-H}. Broken: 5×415+345+350+464+3×498=4728 kJ5 \times 415 + 345 + 350 + 464 + 3 \times 498 = 4728\,\mathrm{kJ}. Formed: 4×741+6×464=5748 kJ4 \times 741 + 6 \times 464 = 5748\,\mathrm{kJ}. Er≈−1020 kJE_r \approx -1020\,\mathrm{kJ}, about a quarter smaller in size than the measured 1367.6 kJ1367.6\,\mathrm{kJ}.

Exercise 37.8 ★★

Compute the energy released per kilogram of propane (2219.2 kJ/mol2219.2\,\mathrm{kJ}/\mathrm{mol}) and of methane. Compare with the bar chart.

Solution

Solution of Exercise 37.8.

Propane: 2219.2/0.0440=5.04×104 kJ/kg=50.4 MJ/kg2219.2 / 0.0440 = 5.04 \times 10^{4}\,\mathrm{kJ}/\mathrm{kg} = 50.4\,\mathrm{MJ}/\mathrm{kg}. Methane: 890.7/0.0160=55.7 MJ/kg890.7 / 0.0160 = 55.7\,\mathrm{MJ}/\mathrm{kg}. Both as on the chart.

Exercise 37.9 ★★

A gas cooker heats 1.50 L1.50\,\mathrm{L} of water (1500 g1500\,\mathrm{g}) from 15 ∘C15\,{}^{\circ}\mathrm{C} to 100 ∘C100\,{}^{\circ}\mathrm{C}. What energy does the water receive? What mass of methane is burnt if all the energy reached the water? If only half of it did?

Solution

Solution of Exercise 37.9.

Q=1500×4.18×85=5.33×105 J=533 kJQ = 1500 \times 4.18 \times 85 = 5.33 \times 10^{5}\,\mathrm{J} = 533\,\mathrm{kJ}; n=533/890.7=0.598 moln = 533 / 890.7 = 0.598\,\mathrm{mol}, that is 0.598×16.0=9.6 g0.598 \times 16.0 = 9.6\,\mathrm{g} of methane; with half the energy lost, 19 g19\,\mathrm{g}.

Exercise 37.10 ★★

Using the bar chart, rank the fuels by energy per kilogram. What mass of hydrogen gives the same energy as 1.0 kg1.0\,\mathrm{kg} of octane?

Solution

Solution of Exercise 37.10.

Hydrogen > methane > propane > octane > ethanol. 48.0/142.9=0.34 kg48.0 / 142.9 = 0.34\,\mathrm{kg} of hydrogen.

Exercise 37.11 ★★

Estimate the energy of NX2+3 HX2→2 NHX3\ce{N2 + 3H2 -> 2NH3}, all gases. Exothermic or endothermic?

Solution

Solution of Exercise 37.11.

Broken: 946+3×436=2254 kJ946 + 3 \times 436 = 2254\,\mathrm{kJ}; formed: 6×390=2340 kJ6 \times 390 = 2340\,\mathrm{kJ}; Er≈−86 kJE_r \approx -86\,\mathrm{kJ}: slightly exothermic.

Exercise 37.12 ★★★

In a spirit-burner experiment, 250 g250\,\mathrm{g} of water warm by 20 ∘C20\,{}^{\circ}\mathrm{C} while 1.20 g1.20\,\mathrm{g} of ethanol burn. Compute the energy received by the water, the energy the ethanol could release, and the efficiency of the heating. Name three causes of the losses.

Solution

Solution of Exercise 37.12.

Water: 250×4.18×20=2.09×104 J=20.9 kJ250 \times 4.18 \times 20 = 2.09 \times 10^{4}\,\mathrm{J} = 20.9\,\mathrm{kJ}. Ethanol: 1.20/46.0=0.0261 mol1.20 / 46.0 = 0.0261\,\mathrm{mol}, which could release 0.0261×1367.6=35.7 kJ0.0261 \times 1367.6 = 35.7\,\mathrm{kJ}. Efficiency 20.9/35.7≈59 %20.9 / 35.7 \approx 59\,\%. Losses: heat carried away by the air, heat warming the can and the stand, incomplete combustion (soot), some ethanol evaporating unburnt.

Exercise 37.13 ★★★

Octane releases 5470 kJ/mol5470\,\mathrm{kJ}/\mathrm{mol} and propane 2219.2 kJ/mol2219.2\,\mathrm{kJ}/\mathrm{mol}. Write their combustion equations and compute the mass of carbon dioxide each releases per megajoule. Compare with methane, 49.4 g49.4\,\mathrm{g}.

Solution

Solution of Exercise 37.13.

2 CX8HX18+25 OX2→16 COX2+18 HX2O\ce{2C8H18 + 25O2 -> 16CO2 + 18H2O}: 8 moles of carbon dioxide, 352 g352\,\mathrm{g}, per 5470 kJ5470\,\mathrm{kJ}, so 352/5.470=64.4 g352 / 5.470 = 64.4\,\mathrm{g} per megajoule. CX3HX8+5 OX2→3 COX2+4 HX2O\ce{C3H8 + 5O2 -> 3CO2 + 4H2O}: 132 g132\,\mathrm{g} per 2219.2 kJ2219.2\,\mathrm{kJ}, so 59.5 g59.5\,\mathrm{g} per megajoule. Methane, with 49.4 g49.4\,\mathrm{g}, releases the least.

Exercise 37.14 ★★★

For both methane and ethanol, the bond-energy estimate is smaller than the measured energy released. Give the reasons, and explain why the estimate is still useful.

Solution

Solution of Exercise 37.14.

The table gives average bond energies, while the C=O\ce{C=O} bonds of carbon dioxide are stronger than average; the measured values are for liquid water, whose condensation releases more energy than the gas reaction; and the method treats every bond as independent of its neighbours. The estimate is still useful: it gives the right sign (exothermic) and the right order of magnitude without any measurement.

Exercise 37.15 ★★★

Estimate the energy of 2 HX2O→2 HX2+OX2\ce{2H2O -> 2H2 + O2}, all gases. Why must energy be supplied (for example as electricity) to make hydrogen from water? Explain why hydrogen is called a way of storing energy rather than a source of energy.

Solution

Solution of Exercise 37.15.

Broken: 4×464=1856 kJ4 \times 464 = 1856\,\mathrm{kJ}; formed: 2×436+498=1370 kJ2 \times 436 + 498 = 1370\,\mathrm{kJ}; Er≈+486 kJE_r \approx +486\,\mathrm{kJ}: endothermic, so energy must be supplied. Burning the hydrogen later gives this energy back: hydrogen stores energy produced elsewhere, it does not create any.

37.6 Problem: Which Fuel for the City Bus?

Problem 37.1

Weekend problem — methane, ethanol, octane or hydrogen: which gives the most energy per kilogram, and how much carbon dioxide per megajoule?

A city compares four fuels for its buses: methane (natural gas), ethanol, octane (for petrol) and hydrogen. The energies released by the complete combustion of one mole are: methane 890.7 kJ890.7\,\mathrm{kJ}, ethanol 1367.6 kJ1367.6\,\mathrm{kJ}, octane 5470 kJ5470\,\mathrm{kJ}, hydrogen 285.8 kJ285.8\,\mathrm{kJ}, the water being formed liquid.

Part I — Combustion equations.

  1. Write the equation of the complete combustion of methane.
  2. Of ethanol, CX2HX6O\ce{C2H6O}.
  3. Of octane, CX8HX18\ce{C8H18}.
  4. Of hydrogen.
  5. Which fuel releases no carbon dioxide?

Part II — Energy per kilogram.

  1. Compute the molar masses of the four fuels.
  2. Compute the energy released per kilogram for each, in MJ/kg\mathrm{MJ}/\mathrm{kg}.
  3. Rank the fuels.
  4. Hydrogen wins by far. Why is it still difficult to carry on a bus? (Think of its state at room temperature.)

Part III — Estimating with bond energies.

  1. Draw the Lewis structures of the molecules of the combustion of methane, and count the bonds broken and formed.
  2. Compute the energy needed to break the bonds.
  3. Compute the energy released by forming the new bonds.
  4. Deduce the estimate of ErE_r, and compare with the measured value: relative difference?
  5. Give two reasons for the difference.

Part IV — Carbon dioxide per megajoule.

  1. What amount of methane must burn to release 1 MJ1\,\mathrm{MJ}?
  2. What mass of carbon dioxide does it release?
  3. Same question for ethanol and octane.
  4. Which carbon fuel releases the least carbon dioxide for the same energy? Why (compare the numbers of C and H atoms)?
  5. Hydrogen releases none when it burns. On what does its true benefit for the climate depend?
  6. State the final answer: what mass of carbon dioxide does methane release per megajoule?
Solution

Solution of Problem 37.1.

1. CHX4+2 OX2→COX2+2 HX2O\ce{CH4 + 2O2 -> CO2 + 2H2O}.

2. CX2HX6O+3 OX2→2 COX2+3 HX2O\ce{C2H6O + 3O2 -> 2CO2 + 3H2O}.

3. 2 CX8HX18+25 OX2→16 COX2+18 HX2O\ce{2C8H18 + 25O2 -> 16CO2 + 18H2O}.

4. 2 HX2+OX2→2 HX2O\ce{2H2 + O2 -> 2H2O}.

5. Hydrogen.

6. 16.0 g/mol16.0\,\mathrm{g}/\mathrm{mol}, 46.0 g/mol46.0\,\mathrm{g}/\mathrm{mol}, 114.0 g/mol114.0\,\mathrm{g}/\mathrm{mol}, 2.0 g/mol2.0\,\mathrm{g}/\mathrm{mol}.

7. In kJ\mathrm{kJ} per kg\mathrm{kg}, then MJ/kg\mathrm{MJ}/\mathrm{kg}: methane 890.7/0.0160890.7 / 0.0160, 55.7 MJ/kg55.7\,\mathrm{MJ}/\mathrm{kg}; ethanol 1367.6/0.04601367.6 / 0.0460, 29.7 MJ/kg29.7\,\mathrm{MJ}/\mathrm{kg}; octane 5470/0.11405470 / 0.1140, 48.0 MJ/kg48.0\,\mathrm{MJ}/\mathrm{kg}; hydrogen 285.8/0.0020285.8 / 0.0020, 142.9 MJ/kg142.9\,\mathrm{MJ}/\mathrm{kg}.

8. Hydrogen > methane > octane > ethanol.

9. Hydrogen is a very light gas: a kilogram of it fills a huge volume at normal pressure, so it must be squeezed into heavy high-pressure tanks.

10. Methane: 4 C−H\ce{C-H}; dioxygen: 2 O=O\ce{O=O} broken. Carbon dioxide: 2 C=O\ce{C=O}; water: 2×2=42 \times 2 = 4 O−H\ce{O-H} formed.

11. 4×415+2×498=2656 kJ4 \times 415 + 2 \times 498 = 2656\,\mathrm{kJ}.

12. 2×741+4×464=3338 kJ2 \times 741 + 4 \times 464 = 3338\,\mathrm{kJ}.

13. Er≈2656−3338=−682 kJE_r \approx 2656 - 3338 = -682\,\mathrm{kJ}, against −890.7 kJ-890.7\,\mathrm{kJ} measured: about 23 %23\,\% too small in size.

14. Average bond energies (the C=O\ce{C=O} of carbon dioxide is stronger than average); liquid water in the measurement, gases in the estimate.

15. 1000/890.7=1.123 mol1000 / 890.7 = 1.123\,\mathrm{mol}.

16. 1.123×44.0=49.4 g1.123 \times 44.0 = 49.4\,\mathrm{g}.

17. Ethanol: 1000/1367.6=0.731 mol1000 / 1367.6 = 0.731\,\mathrm{mol}, giving 1.462 mol1.462\,\mathrm{mol} of carbon dioxide, 64.3 g64.3\,\mathrm{g}. Octane: 1000/5470=0.183 mol1000 / 5470 = 0.183\,\mathrm{mol}, giving 1.463 mol1.463\,\mathrm{mol}, 64.4 g64.4\,\mathrm{g}.

18. Methane: it has the most hydrogen atoms per carbon atom (4 against 2.25 for octane), and burning hydrogen gives energy without carbon dioxide.

19. On how the hydrogen is made: from water with electricity from renewable sources, it releases almost no carbon dioxide; made from methane, it releases carbon dioxide at the factory instead of the exhaust.

20. Methane releases about 49 g49\,\mathrm{g} of carbon dioxide per megajoule.

Terms defined in this chapter

See all 852 terms in the glossary