Mathematics · Book 1 · Grades 1–9

Primary & Middle School Mathematics

Primary & Middle School Mathematics · Grades 1–9

20Solving Problems

Knowing the four operations is one thing; knowing which one a story needs is another. This chapter gives a method for word problems — the same four steps every time — and teaches how to read information from tables and pictograms.

20.1 The four steps

Method 20.1 (Solving a word problem)

  1. Read the problem twice; say in your own words what is asked, and what is known.
  2. Choose the operation: draw a quick sketch or a bar picture if the choice is not obvious.
  3. Compute, in columns or mentally, with an estimate as a safety net.
  4. Answer with a full sentence, including the unit — and check the answer makes sense (a child does not weigh 300300 kg).

Example 20.2 (Which operation?)

The words hint at the operation, the sketch decides:

  • putting together / in all: addition;
  • taking away / how many more / what is missing: subtraction;
  • so many groups of so many / so many times: multiplication;
  • sharing fairly / how many groups: division.
Bar pictures make the operation visible: parts side by side call for an addition; two bars compared call for a subtraction.
Bar pictures make the operation visible: parts side by side call for an addition; two bars compared call for a subtraction.

Example 20.3 (A two-step problem)

“Maya buys 33 packs of 66 bottles and drinks 22 bottles. How many bottles are left?”

  1. What is asked: the number of bottles remaining. Known: 33 packs of 66; 22 drunk.
  2. Sketch: 33 groups of 66, then take 22 away. Two operations!
  3. Compute: 3×6=183 \times 6 = 18, then 182=1618 - 2 = 16.
  4. Sentence: 1616 bottles are left.

Never stop after the first operation: reread the question to see whether the story is finished.

Example 20.4 (A useless number)

“A baker, who is 5252 years old, bakes 120120 rolls and sells 8585. How many rolls are left?” The age is there to distract you: the answer only needs 12085=35120 - 85 = 35 rolls. Before computing, always sort the numbers: which ones does the question really use?

20.2 Reading tables and pictograms

Example 20.5 (A table)

Books borrowed at the library:

comicsnovelssciencetotal
week 1141499662929
week 211111212883131

Reading: week 2, novels: 1212. Computing from the table: in the two weeks together, 14+11=2514 + 11 = 25 comics were borrowed; the busiest week was week 2 (31>2931 > 29).

Example 20.6 (A pictogram)

In a pictogram, one symbol stands for a fixed amount — read the key first!

A pictogram: Monday shows 3 dots, so 3 × 4 = 12 cakes; Tuesday 5 dots, 20 cakes; Wednesday 3 dots, 12 cakes.
A pictogram: Monday shows 33 dots, so 3×4=123 \times 4 = 12 cakes; Tuesday 55 dots, 2020 cakes; Wednesday 33 dots, 1212 cakes.

20.3 Exercises

Exercise 20.1

For each story, just name the operation (do not compute): a flock of 4848 sheep joins a flock of 3737; 5656 cherries shared among 77 children; 99 boxes of 88 pencils; Ali had 7171 cards and gave away 1818.

Solution

Solution of Exercise 20.1.

Flocks joining: addition. Sharing cherries: division. Boxes of pencils: multiplication. Cards given away: subtraction.

Exercise 20.2

Solve with the four steps: “A parking lot has 246246 cars in the morning; 158158 more arrive at noon. How many cars are there now?”

Solution

Solution of Exercise 20.2.

Asked: the number of cars now. Known: 246246, then 158158 more. Operation: addition. Compute: 246+158=404246 + 158 = 404. Sentence: there are now 404404 cars in the parking lot.

Exercise 20.3

Solve: “A rope of 9090 m is cut into pieces of 99 m. How many pieces?”

Solution

Solution of Exercise 20.3.

Grouping division: 90÷9=1090 \div 9 = 10. The rope gives 1010 pieces.

Exercise 20.4

Solve: “Tickets cost 88 each. What do 2626 tickets cost?”

Solution

Solution of Exercise 20.4.

Multiplication: 26×8=20826 \times 8 = 208. The tickets cost 208208.

Exercise 20.5

Draw a bar picture, then solve: “Emma has 6464 stickers, Hugo has 2929 fewer. How many has Hugo?”

Solution

Solution of Exercise 20.5.

Comparison bar: Emma’s bar 6464, Hugo’s bar shorter by 2929. Subtraction: 6429=3564 - 29 = 35. Hugo has 3535 stickers.

Exercise 20.6

Two steps: “A crate holds 4545 apples. A grocer receives 66 crates and sells 178178 apples. How many apples remain?”

Solution

Solution of Exercise 20.6.

Received: 6×45=2706 \times 45 = 270 apples. Remaining: 270178=92270 - 178 = 92 apples.

Exercise 20.7

Using the table of Example 20.5: how many science books were borrowed in the two weeks together? How many more novels in week 2 than in week 1?

Solution

Solution of Exercise 20.7.

Science books: 6+8=146 + 8 = 14. Novels: 129=312 - 9 = 3 more in week 2.

Exercise 20.8

Using the pictogram of Example 20.6: how many cakes were sold in the three days together? On which day were the most cakes sold?

Solution

Solution of Exercise 20.8.

Monday 1212, Tuesday 2020, Wednesday 1212: total 12+20+12=4412 + 20 + 12 = 44 cakes. The best day was Tuesday.

Exercise 20.9

This problem has a useless number — find it, then solve: “A 210210-page book costs 1212. Leo reads 3535 pages a day. How many days does he need to finish the book?”

Solution

Solution of Exercise 20.9.

The useless number is the price (1212). Division: 210÷35=6210 \div 35 = 6 (since 35×6=21035 \times 6 = 210). Leo needs 66 days.

Exercise 20.10 ★★

“A family of 22 adults and 33 children visits the museum. Adult tickets cost 99, children tickets 44. They pay with a 5050 bill. How much change do they get?” (Three steps: adults, children, then the change.)

Solution

Solution of Exercise 20.10.

Adults: 2×9=182 \times 9 = 18. Children: 3×4=123 \times 4 = 12. Total price: 18+12=3018 + 12 = 30. Change: 5030=2050 - 30 = 20. They get 2020 back.

Exercise 20.11 ★★

Make up your own two-step problem whose answer is 100100, write its solution with the four steps, and test it on a classmate.

Solution

Solution of Exercise 20.11.

Many correct answers — for instance: “A florist makes 88 bunches of 1515 flowers, then removes 2020 wilted flowers. How many flowers remain?” Solution: 8×15=1208 \times 15 = 120, then 12020=100120 - 20 = 100.