Mathematics · Book 1 · Grades 1–9

Primary & Middle School Mathematics

Primary & Middle School Mathematics · Grades 1–9

47Fractions: Comparing and Adding

Grade 6 introduced fractions as shares and as exact quotients (Chapter 39). This chapter learns to compute with them: recognizing equal fractions, comparing, adding and subtracting — for now with friendly denominators; the general case comes in Chapter 63.

47.1 Equal fractions

Theorem 47.1 (Equal fractions)

A fraction is unchanged when its numerator and denominator are multiplied, or divided, by the same nonzero number:

ab=a×kb×k.\frac{a}{b} = \frac{a \times k}{b \times k} .

Proof. Admitted at this level.

Example 47.2

34=3×54×5=1520\dfrac{3}{4} = \dfrac{3 \times 5}{4 \times 5} = \dfrac{15}{20}, and in the other direction 4230=42÷630÷6=75\dfrac{42}{30} = \dfrac{42 \div 6}{30 \div 6} = \dfrac{7}{5} (simplified by 66).

To test whether 812\dfrac{8}{12} and 1015\dfrac{10}{15} are equal, simplify both: 812=23\dfrac{8}{12} = \dfrac{2}{3} and 1015=23\dfrac{10}{15} = \dfrac{2}{3} — yes, equal.

47.2 Comparing fractions

Method 47.3 (Comparing two fractions)

  1. Same denominator: compare the numerators: 59<79\frac{5}{9} < \frac{7}{9}.
  2. One denominator is a multiple of the other: rewrite the coarser fraction, then compare: 56\frac{5}{6} vs 712\frac{7}{12}: 56=1012>712\frac56 = \frac{10}{12} > \frac{7}{12}.
  3. Compare with 11 or 12\frac12 when possible: 98>1>79\frac{9}{8} > 1 > \frac{7}{9} settles 98\frac98 vs 79\frac79 instantly.
Comparing 5/6 and 7/12 on twin bars: cutting the sixths in half shows 5/6 = 10/12, more than 7/12.
Comparing 56\frac56 and 712\frac{7}{12} on twin bars: cutting the sixths in half shows 56=1012\frac56 = \frac{10}{12}, more than 712\frac{7}{12}.

47.3 Adding and subtracting

Theorem 47.4 (Same denominator)

Fractions with the same denominator are added (or subtracted) by adding (or subtracting) the numerators:

ad+bd=a+bd,adbd=abd.\frac{a}{d} + \frac{b}{d} = \frac{a + b}{d}, \qquad \frac{a}{d} - \frac{b}{d} = \frac{a - b}{d} .

Why. aa parts of size 1d\frac1d plus bb parts of the same size make a+ba + b parts of that size.

Method 47.5 (Different denominators)

When one denominator is a multiple of the other:

  1. rewrite the fraction with the smaller denominator so both have the larger one (Theorem 47.1);
  2. add or subtract the numerators;
  3. simplify the result if possible.

Example 47.6

Compute 34+58\dfrac{3}{4} + \dfrac{5}{8}, step by step:

  1. 88 is a multiple of 44: rewrite 34=3×24×2=68\dfrac34 = \dfrac{3 \times 2}{4 \times 2} = \dfrac{6}{8};
  2. add: 68+58=118\dfrac{6}{8} + \dfrac{5}{8} = \dfrac{11}{8};
  3. nothing to simplify: the result is 118\dfrac{11}{8}, i.e. 1+381 + \dfrac38.

Another: 245=10545=652 - \dfrac{4}{5} = \dfrac{10}{5} - \dfrac{4}{5} = \dfrac{6}{5} (write the whole number over the denominator 55 first).

Example 47.7 (A classic trap)

12+13\dfrac12 + \dfrac13 is not 25\dfrac{2}{5}! Adding numerators and denominators separately is wrong — the answer 25\frac25 would be smaller than 12\frac12, absurd when adding something positive to 12\frac12. (The correct sum, 56\frac56, needs a common denominator 66; the general method is in Chapter 63.)

47.4 Multiplying a fraction by a number

Proposition 47.8 (Fraction times a number)

For a number kk:

k×ab=k×ab.k \times \frac{a}{b} = \frac{k \times a}{b} .

Taking ab\frac ab of a quantity means multiplying by ab\frac ab.

Proof. Admitted at this level.

Example 47.9

6×23=123=46 \times \dfrac{2}{3} = \dfrac{12}{3} = 4: six times two thirds is four wholes. And “34\frac34 of 6060 euros” is 34×60=1804=45\frac34 \times 60 = \frac{180}{4} = 45 euros — the same answer as dividing by 44 then multiplying by 33 (Method 39.8).

47.5 Exercises

Exercise 47.1

Complete: 25=?20\dfrac{2}{5} = \dfrac{?}{20}; 1824=3?\dfrac{18}{24} = \dfrac{3}{?}; 73=28?\dfrac{7}{3} = \dfrac{28}{?}; ?9=2036\dfrac{?}{9} = \dfrac{20}{36}.

Solution

Solution of Exercise 47.1.

25=820\dfrac{2}{5} = \dfrac{8}{20}; 1824=34\dfrac{18}{24} = \dfrac{3}{4}; 73=2812\dfrac{7}{3} = \dfrac{28}{12}; 59=2036\dfrac{5}{9} = \dfrac{20}{36}.

Exercise 47.2

Simplify as much as possible: 1216\dfrac{12}{16}; 3045\dfrac{30}{45}; 2736\dfrac{27}{36}; 4812\dfrac{48}{12}.

Solution

Solution of Exercise 47.2.

1216=34\dfrac{12}{16} = \dfrac34; 3045=23\dfrac{30}{45} = \dfrac23; 2736=34\dfrac{27}{36} = \dfrac34; 4812=4\dfrac{48}{12} = 4.

Exercise 47.3

Are 1535\dfrac{15}{35} and 2149\dfrac{21}{49} equal? And 1628\dfrac{16}{28} and 2036\dfrac{20}{36}? Justify by simplifying.

Solution

Solution of Exercise 47.3.

1535=37\dfrac{15}{35} = \dfrac37 and 2149=37\dfrac{21}{49} = \dfrac37: equal.

1628=47\dfrac{16}{28} = \dfrac47 and 2036=59\dfrac{20}{36} = \dfrac59: to compare, 47=3663\frac47 = \frac{36}{63} and 59=3563\frac59 = \frac{35}{63} — not equal.

Exercise 47.4

Compare (write the reasoning, not just the answer):

711 and 911;56 and 1118;1312 and 1920.\frac{7}{11} \text{ and } \frac{9}{11}; \qquad \frac{5}{6} \text{ and } \frac{11}{18}; \qquad \frac{13}{12} \text{ and } \frac{19}{20}.
Solution

Solution of Exercise 47.4.

711<911\dfrac{7}{11} < \dfrac{9}{11} (same denominator).

56=1518>1118\dfrac56 = \dfrac{15}{18} > \dfrac{11}{18}.

1312>1\dfrac{13}{12} > 1 while 1920<1\dfrac{19}{20} < 1, so 1312>1920\dfrac{13}{12} > \dfrac{19}{20}.

Exercise 47.5

Compute and simplify if possible:

59+29,11747,58+78.\frac{5}{9} + \frac{2}{9}, \qquad \frac{11}{7} - \frac{4}{7}, \qquad \frac{5}{8} + \frac{7}{8} .
Solution

Solution of Exercise 47.5.

59+29=79\dfrac59 + \dfrac29 = \dfrac79; 11747=77=1\dfrac{11}{7} - \dfrac47 = \dfrac77 = 1; 58+78=128=32\dfrac58 + \dfrac78 = \dfrac{12}{8} = \dfrac32.

Exercise 47.6

Compute using Method 47.5:

23+56,71025,34+512.\frac{2}{3} + \frac{5}{6}, \qquad \frac{7}{10} - \frac{2}{5}, \qquad \frac{3}{4} + \frac{5}{12} .
Solution

Solution of Exercise 47.6.

23+56=46+56=96=32\dfrac23 + \dfrac56 = \dfrac46 + \dfrac56 = \dfrac96 = \dfrac32.

71025=710410=310\dfrac{7}{10} - \dfrac25 = \dfrac{7}{10} - \dfrac{4}{10} = \dfrac{3}{10}.

34+512=912+512=1412=76\dfrac34 + \dfrac{5}{12} = \dfrac{9}{12} + \dfrac{5}{12} = \dfrac{14}{12} = \dfrac76.

Exercise 47.7

Compute:

354,1+38,276.3 - \frac{5}{4}, \qquad 1 + \frac{3}{8}, \qquad 2 - \frac{7}{6} .
Solution

Solution of Exercise 47.7.

354=12454=743 - \dfrac54 = \dfrac{12}{4} - \dfrac54 = \dfrac74; 1+38=1181 + \dfrac38 = \dfrac{11}{8}; 276=12676=562 - \dfrac76 = \dfrac{12}{6} - \dfrac76 = \dfrac56.

Exercise 47.8

Compute:

5×310,78×4,23 of 45.5 \times \frac{3}{10}, \qquad \frac{7}{8} \times 4, \qquad \frac{2}{3} \text{ of } 45 .
Solution

Solution of Exercise 47.8.

5×310=1510=325 \times \dfrac{3}{10} = \dfrac{15}{10} = \dfrac32; 78×4=288=72\dfrac78 \times 4 = \dfrac{28}{8} = \dfrac72; 23\dfrac23 of 4545 is 2×453=903=30\dfrac{2 \times 45}{3} = \dfrac{90}{3} = 30.

Exercise 47.9 ★★

Marc ate 14\frac14 of a pizza and Julie 38\frac38 of the same pizza. What fraction of the pizza did they eat together? What fraction is left?

Solution

Solution of Exercise 47.9.

Together: 14+38=28+38=58\dfrac14 + \dfrac38 = \dfrac28 + \dfrac38 = \dfrac58 of the pizza. Left: 158=381 - \dfrac58 = \dfrac38.

Exercise 47.10 ★★

A bottle contains 34\frac34 L of juice. Lea pours out 16\frac16 L twice. How much juice remains? (Common denominator: 1212.)

Solution

Solution of Exercise 47.10.

Poured out: 2×16=26=132 \times \dfrac16 = \dfrac26 = \dfrac13 L. Remaining:

3413=912412=512 L.\frac34 - \frac13 = \frac{9}{12} - \frac{4}{12} = \frac{5}{12} \text{ L}.

Exercise 47.11 ★★

Explain, with the argument of Example 47.7, why 35+12\frac35 + \frac12 cannot be 47\frac{4}{7}, without computing the correct sum.

Solution

Solution of Exercise 47.11.

Adding the positive quantity 12\frac12 to 35\frac35 must give a result larger than 35\frac35. But 47<35\frac47 < \frac35 (indeed 47=2035\frac47 = \frac{20}{35} and 35=2135\frac35 = \frac{21}{35}): the claimed sum is smaller than one of its terms — impossible.

Exercise 47.12 ★★★

Compute the sum

12+14+18+116\frac12 + \frac14 + \frac18 + \frac{1}{16}

step by step (left to right). Observe the pattern of the partial sums: what number do they approach as more and more terms 132,164,\frac{1}{32}, \frac{1}{64}, \dots are added?

Solution

Solution of Exercise 47.12.

Step by step:

12+14=34,34+18=68+18=78,78+116=1416+116=1516.\frac12 + \frac14 = \frac34, \qquad \frac34 + \frac18 = \frac68 + \frac18 = \frac78, \qquad \frac78 + \frac1{16} = \frac{14}{16} + \frac1{16} = \frac{15}{16}.

The partial sums 12,34,78,1516,\frac12, \frac34, \frac78, \frac{15}{16}, \dots are each time half-way closer to 11: at every step, the missing part is cut in half. The sums approach 11 without ever reaching it.

47.6 Problem: The fractions hidden in a bar of music

Problem 47.1

Weekend problem — note values are fractions that must add up exactly, rhythm counting hides a famous sequence, and parity rules the Balkan beat

Music is written in fractions. A whole note lasts 11 measure (in the common “four-four” time); a half note lasts 12\frac12; then come the quarter note 14\frac14, the eighth note 18\frac18 and the sixteenth note 116\frac{1}{16}. One inviolable law: the durations inside a measure must add up to exactly the measure’s total11 in four-four time. Every question below is this chapter’s arithmetic (Theorem 47.4, Method 47.5) set to music; on the way you will meet a counting sequence discovered by Indian scholars a thousand years ago.

Part I — Notes that must add up.

  1. Check that each of these measures is legal in four-four time: (a) half ++ quarter ++ quarter; (b) quarter ++ eighth ++ eighth ++ half.
  2. A copyist wrote: half ++ quarter ++ eighth. What fraction of the measure is written, and which single note completes it?
  3. How many sixteenth notes fill one whole measure? How many sixteenths make one eighth note?
  4. A dot after a note adds half the note’s value: a dotted half is 12+14\frac12 + \frac14, a dotted quarter is 14+18\frac14 + \frac18. Compute both values.
  5. A waltz is written in three-four time: each measure must total 34\frac34. Check that a single dotted half fills a waltz measure, and write down two other legal waltz measures using only quarters and eighths.

Part II — The copyist’s workshop.

  1. A four-four measure contains: dotted quarter ++ eighth ++ quarter. What is missing?
  2. Which lasts longer, a dotted eighth or a quarter note? Compare via sixteenths.
  3. A tie glues durations together into one long sound: a half note tied to an eighth lasts how long? How many sixteenths is that?
  4. The notes of a measure add up to 1116\frac{11}{16}; the remainder is silence (a rest). How long is the rest?
  5. A drummer fills one quarter note (416\frac{4}{16} of the measure) using only eighths (216\frac{2}{16}) and sixteenths (116\frac{1}{16}), order mattering: for instance eighth–sixteenth–sixteenth, or sixteenth–eighth–sixteenth. Check that both examples are legal, then list all the possible rhythms. How many are there?

Part III — A thousand-year-old sequence, and an odd measure.

  1. Let us count the drummer’s rhythms for longer notes. Every rhythm ends either with a sixteenth or with an eighth; explain why this gives the rule: (rhythms filling nn sixteenths) == (rhythms filling n1n - 1) ++ (rhythms filling n2n - 2). Starting from 11 rhythm for one sixteenth and 22 for two, build the table up to n=8n = 8: how many rhythms fill a half note?
  2. The numbers you found — 1,2,3,5,8,13,21,341, 2, 3, 5, 8, 13, 21, 34 — were published by the Indian scholar Hemachandra around the year 1150, counting exactly such rhythms, two generations before Fibonacci wrote them down in Italy. State their defining pattern in one sentence, and check it on the last three entries of your table.
  3. “Swing” style replaces two equal eighths by a long–short pair: 16\frac16 then 112\frac{1}{12}. Verify that the swap is legal (same total duration), using the common denominator 1212.
  4. A triplet squeezes three equal notes into one quarter note. How long is each note (check your answer by multiplying it by 33, Proposition 47.8)? Same question for three equal notes filling a half note.
  5. Balkan dance music uses seven-eight time: each measure totals 78\frac78. Verify that dotted quarter ++ quarter ++ quarter fills it. Then explain why no combination of half notes and quarter notes alone, however many, can ever fill a seven-eight measure. (Count in eighths and think about even and odd.)
Solution

Solution of Problem 47.1.

1. (a) 12+14+14=24+14+14=44=1\frac12 + \frac14 + \frac14 = \frac24 + \frac14 + \frac14 = \frac44 = 1: legal. (b) 14+18+18+12=28+18+18+48=88=1\frac14 + \frac18 + \frac18 + \frac12 = \frac28 + \frac18 + \frac18 + \frac48 = \frac88 = 1: legal.

2. 12+14+18=48+28+18=78\frac12 + \frac14 + \frac18 = \frac48 + \frac28 + \frac18 = \frac78: one eighth note is missing.

3. A measure is 1=16161 = \frac{16}{16}: sixteen sixteenth notes. An eighth is 18=216\frac18 = \frac{2}{16}: two sixteenths.

4. Dotted half: 12+14=34\frac12 + \frac14 = \frac34. Dotted quarter: 14+18=28+18=38\frac14 + \frac18 = \frac28 + \frac18 = \frac38.

5. The dotted half is worth 34\frac34 (question 4): exactly one waltz measure. Other fillings, for instance: quarter ++ quarter ++ quarter (14+14+14=34\frac14 + \frac14 + \frac14 = \frac34), or quarter ++ eighth ++ eighth ++ quarter (14+18+18+14=2+1+1+28=68=34\frac14 + \frac18 + \frac18 + \frac14 = \frac{2 + 1 + 1 + 2}{8} = \frac68 = \frac34).

6. 38+18+14=38+18+28=68=34\frac38 + \frac18 + \frac14 = \frac38 + \frac18 + \frac28 = \frac68 = \frac34: one quarter note (14\frac14) is missing.

7. Dotted eighth: 18+116=216+116=316\frac18 + \frac{1}{16} = \frac{2}{16} + \frac{1}{16} = \frac{3}{16}. Quarter: 416\frac{4}{16}. The quarter is longer.

8. 12+18=48+18=58\frac12 + \frac18 = \frac48 + \frac18 = \frac58, that is 1016\frac{10}{16}: ten sixteenths.

9. 11116=16161116=5161 - \frac{11}{16} = \frac{16}{16} - \frac{11}{16} = \frac{5}{16} of the measure is silence.

10. Both examples total 2+1+116=416\frac{2 + 1 + 1}{16} = \frac{4}{16}: legal. All rhythms filling four sixteenths with pieces of 22 and 11:

2+2,2+1+1,1+2+1,1+1+2,1+1+1+1:2{+}2, \quad 2{+}1{+}1, \quad 1{+}2{+}1, \quad 1{+}1{+}2, \quad 1{+}1{+}1{+}1 :

five rhythms.

11. A rhythm filling nn sixteenths ends either with a sixteenth — and what precedes fills n1n - 1 — or with an eighth — and what precedes fills n2n - 2. Every rhythm is counted exactly once this way, so ways(n)=ways(n1)+ways(n2)\text{ways}(n) = \text{ways}(n-1) + \text{ways}(n-2). Table:

nn1122334455667788
ways1122335588131321213434

A half note (88 sixteenths) can be drummed in 3434 ways. (n=4n = 4 recovers the five rhythms of question 10.)

12. Each number is the sum of the two before it: 3+5=83 + 5 = 8, 5+8=135 + 8 = 13, 8+13=218 + 13 = 21, 13+21=3413 + 21 = 34 — the rule question 11 proved, a thousand years old and now known as the Fibonacci rule.

13. 16+112=212+112=312=14\frac16 + \frac{1}{12} = \frac{2}{12} + \frac{1}{12} = \frac{3}{12} = \frac14: the same duration as two straight eighths (18+18=14\frac18 + \frac18 = \frac14). The swing swap is legal.

14. Each triplet note lasts 112\frac{1}{12}: check, 3×112=312=143 \times \frac{1}{12} = \frac{3}{12} = \frac14 (Proposition 47.8). For a half note: each lasts 16\frac16, since 3×16=36=123 \times \frac16 = \frac36 = \frac12.

15. Dotted quarter ++ quarter ++ quarter: in eighths, 3+2+2=73 + 2 + 2 = 7 eighths =78= \frac78: legal. Halves and quarters are worth 44 and 22 eighths — both even numbers. Any sum of even numbers is even, but a seven-eight measure needs 77 eighths, an odd number: impossible. To fill an odd measure, something odd — an eighth or a dotted note — must appear.