Mathematics · Book 1 · Grades 1–9

Primary & Middle School Mathematics

Primary & Middle School Mathematics · Grades 1–9

36Problems and Charts

The last chapter of the year puts everything to work: multi-step problems with money, quantities and durations, and the charts that present information at a glance. The star idea is “per one” — finding the price of a single item — which will grow into proportionality in Chapter 44.

36.1 Multi-step problems

Method 36.1 (Taming a long problem)

  1. Read to the end; say what the final question is;
  2. plan backwards: to answer it, what do I need first?
  3. solve the steps in order, writing one operation and one short sentence per step;
  4. check the final answer against common sense and against an estimate.

Example 36.2

“A school orders 44 boxes of 2525 books at 66 each, and pays 180180 for delivery on top. What is the total cost?”

  1. Books: 4×25=1004 \times 25 = 100 books.
  2. Book cost: 100×6=600100 \times 6 = 600.
  3. Total: 600+180=780600 + 180 = 780.

Estimate check: about a hundred books at 66 is about 600600, plus about 200200: about 800800 — the answer 780780 is plausible.

Example 36.3 (Per one)

55 identical mugs cost 12.5012.50; what do 88 mugs cost?” Find the price of one mug first:

12.50÷5=2.50,then8×2.50=20.12.50 \div 5 = 2.50, \qquad\text{then}\qquad 8 \times 2.50 = 20 .

Through one, everything becomes reachable — this two-step pattern solves a whole family of problems (recipes, speeds, prices), and is the seed of Chapter 44.

Example 36.4 (Change and budget)

Zoe has 3030. She buys a book at 12.4012.40 and two pens at 2.302.30 each. Can she also afford a 1313 board game?

  1. Pens: 2×2.30=4.602 \times 2.30 = 4.60.
  2. Spent so far: 12.40+4.60=1712.40 + 4.60 = 17.
  3. Remaining: 3017=1330 - 17 = 13 — exactly enough for the game, with nothing left.

36.2 Reading charts

Method 36.5 (Reading any chart)

  1. Read the title: what is being counted?
  2. Read the axes or the key: what does one graduation, one bar, one symbol stand for?
  3. Only then answer questions — pointing at the chart with a ruler helps read heights exactly.

Example 36.6

Rainfall in a town, month by month:

A bar chart of rainfall. One graduation = 20 mm.
A bar chart of rainfall. One graduation =20= 20 mm.

Readings: the wettest month is May (8080 mm); June got half of April’s rain (3030 against 7070? no — half of 7070 is 3535, so not quite half: reading precisely matters!); total for the six months: 60+45+55+70+80+30=34060 + 45 + 55 + 70 + 80 + 30 = 340 mm.

Example 36.7 (A changing quantity)

A plant’s height, measured every week:

Joining the measurement points shows the growth: the steeper the segment, the faster the plant grew that week.
Joining the measurement points shows the growth: the steeper the segment, the faster the plant grew that week.

The plant grew fastest between weeks 33 and 44 (+5+5 cm) and slowed down at the end (+2+2 cm in week 66).

36.3 Exercises

Exercise 36.1

Solve in steps: “A club rents a bus for 240240 and buys 3232 museum tickets at 77 each. What is the total cost of the trip?”

Solution

Solution of Exercise 36.1.

Tickets: 32×7=22432 \times 7 = 224. Total: 240+224=464240 + 224 = 464.

Exercise 36.2

Solve with “per one”: “33 kg of apples cost 7.507.50. What do 55 kg cost?”

Solution

Solution of Exercise 36.2.

Per one kg: 7.50÷3=2.507.50 \div 3 = 2.50. Five kg: 5×2.50=12.505 \times 2.50 = 12.50.

Exercise 36.3

Solve: “Six friends share equally the 8787 cost of a picnic. How much does each pay?”

Solution

Solution of Exercise 36.3.

87÷6=14.587 \div 6 = 14.5: each pays 14.5014.50.

Exercise 36.4

Sam has 2525. He buys a T-shirt at 13.9013.90 and a cap at 8.508.50. How much money has he left?

Solution

Solution of Exercise 36.4.

Spent: 13.90+8.50=22.4013.90 + 8.50 = 22.40. Left: 2522.40=2.6025 - 22.40 = 2.60.

Exercise 36.5

Using the rainfall chart of Example 36.6: which months got more than 5050 mm? How much more rain fell in May than in June?

Solution

Solution of Exercise 36.5.

More than 5050 mm: January (6060), March (5555), April (7070), May (8080). May minus June: 8030=5080 - 30 = 50 mm.

Exercise 36.6

Using the plant chart of Example 36.7: how tall was the plant in week 22? Between which weeks did it grow by exactly 44 cm?

Solution

Solution of Exercise 36.6.

Week 22: 66 cm. Growth of 44 cm: between weeks 22 and 33 (6106 \to 10), and between weeks 44 and 55 (151915 \to 19).

Exercise 36.7

Draw a bar chart for the number of goals a team scored: September 44, October 77, November 33, December 66. Choose the graduation, and give the total.

Solution

Solution of Exercise 36.7.

Four bars of heights 44, 77, 33, 66 (graduation every 11 or 22 goals). Total: 4+7+3+6=204 + 7 + 3 + 6 = 20 goals.

Exercise 36.8

A pack of 88 yogurts costs 3.203.20; sold alone, one yogurt costs 0.500.50. Compute the “per one” price in the pack, and how much one saves per yogurt by buying the pack.

Solution

Solution of Exercise 36.8.

Pack per one: 3.20÷8=0.403.20 \div 8 = 0.40. Saving per yogurt: 0.500.40=0.100.50 - 0.40 = 0.10 (ten cents).

Exercise 36.9 ★★

“A cinema sold 148148 tickets at 9.509.50 on Saturday and 9595 tickets at the same price on Sunday. How much more money did Saturday bring than Sunday?” Solve it two ways: computing both days’ takings, or computing with the difference in tickets — and check that the answers agree.

Solution

Solution of Exercise 36.9.

Way 1: Saturday 148×9.50=1406148 \times 9.50 = 1\,406; Sunday 95×9.50=902.5095 \times 9.50 = 902.50; difference 503.50503.50.

Way 2: 14895=53148 - 95 = 53 more tickets, each worth 9.509.50: 53×9.50=503.5053 \times 9.50 = 503.50. Same answer — the difference of the takings is the taking of the difference.

Exercise 36.10 ★★

A recipe for 44 people needs 300300 g of rice. Aline cooks for 1010 people. How much rice does she need? (Per one person first — decimals allowed.)

Solution

Solution of Exercise 36.10.

Per person: 300÷4=75300 \div 4 = 75 g. For ten: 10×75=75010 \times 75 = 750 g of rice.

Exercise 36.11 ★★

Invent a three-step problem using money whose final answer is 5.505.50, write its full solution in the style of Method 36.1, and test it on a classmate.

Solution

Solution of Exercise 36.11.

Many correct problems — for instance: “Milo buys 33 juices at 1.201.20 each and a sandwich at 3.403.40. He pays with a 12.5012.50 voucher. How much of the voucher is left?” Solution: juices 3×1.20=3.603 \times 1.20 = 3.60; total spent 3.60+3.40=73.60 + 3.40 = 7; left 12.507=5.5012.50 - 7 = 5.50.